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-1/4 x + 10=7 show work

Posted on October 23, 2021 By 1thousandwishes 6 Comments on -1/4 x + 10=7 show work

-1/4 x + 10=7 show work

Mathematics

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Comments (6) on “-1/4 x + 10=7 show work”

  1. rol15 says:
    October 23, 2021 at 1:17 pm

    -1/4x+10=7

    -1/4x=7-10

    -1/4x=-3

    -12x=-1

    x=1/12

    Reply
  2. pattay16 says:
    October 23, 2021 at 2:05 pm

    Question: The planck constant was not given. In this calculation, planck constant of 6.62607*10^-9 Js  is used for the calculation.

    (a) A virus Classical

    (b) A buckyball Classical

    (c) A mosquito Quantum

    (d) A turtle  Quantum

    Explanation:

     Calculating the wavelength using the formula;

    λ= h/(mv)

    where

    λ= Wavelength

    h = Planck Constant = 6.62607*10^-9 Js

    m = mass in kg

    v = velocity in m/s

    Virus size = 280. nm = 2.80*10⁻⁷ m

    a)

    A Virus:

    m = 9.4 x 10-17 g 9.4*10⁻²⁰ kg

    v = 0.50 µm/s = 5 *10⁻⁷ m/s

    h = 6.62607*10^-9 Js

    Virus size = 280 nm = 2.80*10⁻⁷ m

    Substituting into the formula; we have

    λ= h/(mv)

    λ= 6.62607*10^-9/ (9.4*10⁻²⁰* 5 *10⁻⁷)

      = 6.62607*10^-9/4.7*10^-26

      = 1.4*10^17 m

    Classical : Wavelength is bigger than it's size

    (b)

    A buckyball

    m = 1.2 x 10-21 g = 1.2 *10⁻²⁴ kg

    V = 37 m/s

    Size = 0.7 nm = 7*10⁻¹⁰ m

    Substituting into the formula, we have

    λ= h/(mv)

    λ= 6.62607*10^-9/ ( 1.2 *10⁻²⁴* 37)

      =  6.62607*10^-9/4.44*10^-23

      = 1.49 *10^14 m

    Classical : Wavelength is bigger than it's size

    (c)

    A mosquito

    Mass = 1.0 mg = 1*10⁻⁶ kg

    v = 1.1 m/s

    Size =  6.3 mm = 6.3*10⁻³ m

    Substituting into the formula, we have

    λ= h/(mv)

    λ= 6.62607*10^-9/ (  1*10⁻⁶* 1.1)

      =  6.62607*10^-9/1.1*10^-6

      = 6.02*10^-3 m

    Quantum Approach: The wavelength and the size are comparable

    (d)

    A turtle

    Mass = 710. g = 0.71 kg

    Size =  22. cm = 0.22 m

    V =  2.8 cm/s. = 0.028 m/s

    Substituting into the formula, we have

    λ= h/(mv)

    λ= 6.62607*10^-9/ (  0.71* 0.028)

      = 6.62607*10^-9/0.01988

       = 3.33*10^-7 m

    Quantum Approach: The wavelength and the size are comparable

    Reply
  3. faithkristi says:
    October 23, 2021 at 7:27 pm

    Content Bot you suck butt

    Step-by-step explanation:

    Reply
  4. sabon says:
    October 23, 2021 at 7:59 pm

    Marisol computed .x2-x1 /y2-y1

    Step-by-step explanation:

    There are two points given

    we have to find the slope of the line.

    we know that the formula for slope of the line when two points are known

    =[tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1}}[/tex]

    Here we have (x1,y1) = (-1,4) and (x2,y2) = (3,10)

    Hence substitute in the formula to get slope of line

    =[tex]\frac{10-4}{3-(-1)} =\frac{3}{2}[/tex]

    Marisol computed .x2-x1 /y2-y1

    So she got wrong slope

    Reply
  5. Meliiiii says:
    October 23, 2021 at 8:11 pm

    Fission

    1.Uranium-235 decays naturally, by alpha decay. Write the balanced decay equation below. (5 points)

    235/92 U = 231/90 Th + 4/2 He (i couldn't type the arrow thingy)

    2.Uranium-235 has a half-life of about 700 million years. If 1 kg of U-235 is put on a shelf in a laboratory, how much of it will be left after 700 million years? (5 points)

    1/2 kg of u-235 I think

    3.Uranium-235 is a popular choice of fuel for nuclear reactors. But U-235 doesn't always fission the same way. Below are three ways it can split. Complete the nuclear equations so they balance. (6 points)

    it can split into Be-56, Pu-52, and un 36.

    4. Instead of allowing 1 kg of U-235 to decay naturally, imagine it is used as fuel in a nuclear

    reactor. It is bombarded with neutrons, causing it all to fission in a matter of days. After 1 kg of U-235 undergoes fission, the mass of the products is 8.4 x 10-4 kg less than the initial 1 kg. How much energy was produced by the fission of 1 kg of U-235? (Hint: Use Einstein's equation, E = mc2, where E is energy in Joules, m is mass in kilograms, and c is the speed of light, 3 x 108 m/s.) (8 points)

    Energy = mc2

    Energy = (8.4 x 10^- 4) (3 x 10^8) ^2

    Energy = 7.56 x 10^13  

    there will be about 75600000000000 or 7.56 x 10^13 joules of energy produced by the fission of 1 kilogram of uranium 235  

    (fact: this one problem alone took me 20 min of checking and rechecking and redoing and starting over to do, and I'm still pretty sure I got the number of 0's at the end wrong lol, though lucky for me I'm in honor's algebra so it didn't take me like 2 years to find the answer UWU)

    Fusion

    5.The fusion of two hydrogen isotopes is shown below. Complete the nuclear equation so it balances. (5 points)

    2/1 H +2/1 H = 4/2 He + 1/0 N

    wow this actually makes sense now

    6.If 1 kg of fuel is used in the above fusion reaction, the resulting helium has a mass of 0.993 kg. In other words, 0.007 kg of mass is converted to energy. How much energy is produced by the fusion of 1 kg of hydrogen? (Hint: Use Einstein's equation, E = mc2, where E is energy in Joules, m is mass in kilograms, and c is the speed of light, 3 x 108 m/s.) (6 points)

    6.3 x 10^14 joules of energy

    Alternative Energy

    7.Hydrogen fuel cells combine hydrogen and oxygen to produce water and energy. Assume 1 kg of fuel is used, and the mass of the water produced is 1.10 x 10-11 kg. How much energy is produced by this fuel cell? (Hint: Use E = mc2.) (7 points)

    5.76 x 10^7 joules of energy.

    Comparison

    8.Complete the following table and questions. (8 points)

    Reaction      Mass "Lost"  Energy Produced

    Fission of 1 kg of U-235  1/2 kg     7.56 x 10^13 joules

    Fusion of 1 kg of hydrogen  1/3 kg     6.3 x 10^13 joules

    Fuel cell with 1 kg of hydrogen and oxygen  1/3 kg   5.4 x 10^13 joules

    Which type of reaction "loses" the most mass?

    the fission reaction of 1 kilogram of uranium 235

    Which type of reaction produces the most energy? Why?

    also the fission reaction of 1 kilogram of uranium 235, one reason that I think it is the reaction that produces more energy than the two other reactions is because of its "mass lost" since it lost 1/6 more mass than the other two reactions, or it might just be the elements that they use since they used uranium for fission, hydrogen for fusion, and hydrogen and oxygen for cell fueling.

    Explanation:

    Reply
  6. anthonyfr10004 says:
    October 24, 2021 at 5:07 am

    y2 - x2/y1 - x1

    Explanation:

    The formula is supposed to be y2 - y1/ x2-x1 to get 6/4 but since Marisol got 7/5, it means Marisol did 10 - 3/ 4-(-1) like  in the steps.

    Reply

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