1. given the functions f(x) = 3x - 4 and g(x) = 4x + 10, find the value of x for which f(x) = g(x).

a. 2

b. -2

c.-6

d. -14

Skip to content# 1. given the functions f(x) = 3x – 4 and g(x) = 4x + 10, find the value of x for which f(x) = g(x).

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1. given the functions f(x) = 3x - 4 and g(x) = 4x + 10, find the value of x for which f(x) = g(x).

a. 2

b. -2

c.-6

d. -14

The answer is D) -14

[tex]f(x)+g(x)=-x+4[/tex]

Step-by-step explanation:

We have the functions, [tex]f(x)=3x-2[/tex] and [tex]g(x)=6-4x[/tex].

It is required to find the sum of these functions.

That is, [tex]f(x)+g(x)[/tex].

On substituting the functions, we get,

[tex]f(x)+g(x)=(3x-2)+(6-4x)[/tex]

i.e. [tex]f(x)+g(x)=(3x-4x)+(6-2)[/tex]

i.e. [tex]f(x)+g(x)=-x+4[/tex]

Thus, the sum of the functions i.e. [tex]f(x)+g(x)=-x+4[/tex].

-x+4 is the answer.

Step-by-step explanation:

We have given two functions.

f(x) = 3x-2

g(x) = 6-4x

We have to find the addition of given two functions.

f(x)+g(x) = ?

Putting given values in above equation, we have

f(x)+g(x) = (3x-2)+(6-4x)

f(x)+g(x) = 3x-2+6-4x

adding like terms ,we have

f(x)+g(x) = (3-4)x+(6-2)

f(x)+g(x) = (-1)x + (4)

f(x)+g(x) = -x +4 which is the answer.

[tex]f(x)+g(x)=3x-2+6-4x=-x+4[/tex]

f(x) = 3x - 2, g(x) = 6 - 4x

f(x) + g(x) = (3x - 2) + (6 - 4x)

= 3x - 2 + 6 - 4x combine like terms

= (3x - 4x) + (-2 + 6)

= -x + 4

Basically substitute f(x) and g(x) in

3x-2+6-4x

Then simplify

-x+4 = 4-x

The answer is B. 4-x

[tex]f(x)+g(x)=3x-2+6-4x=-x+4[/tex]

hehee

Step-by-step explanation:

Idk

N0 (f o g) x = 3x.

Step-by-step explanation:

If they are inverses of each other the f o g will equal x.

f o g = 2(3x +3/ (4x - 2) + 3 / 4(3x + 3)/(4x - 2) - 3)

= 2(3x + 3)+ 3(4x - 2) 4x - 2

*

4x - 2 4(3x + 3) - 3(4x - 2)

6x + 12x

=

12 - 6

= 3x.

So they are not inverses.

D is the right answer