1. given the functions f(x) = 3x - 4 and g(x) = 4x + 10, find the value of x for which f(x) = g(x).
a. 2
b. -2
c.-6
d. -14
1. given the functions f(x) = 3x - 4 and g(x) = 4x + 10, find the value of x for which f(x) = g(x).
a. 2
b. -2
c.-6
d. -14
The answer is D) -14
[tex]f(x)+g(x)=-x+4[/tex]
Step-by-step explanation:
We have the functions, [tex]f(x)=3x-2[/tex] and [tex]g(x)=6-4x[/tex].
It is required to find the sum of these functions.
That is, [tex]f(x)+g(x)[/tex].
On substituting the functions, we get,
[tex]f(x)+g(x)=(3x-2)+(6-4x)[/tex]
i.e. [tex]f(x)+g(x)=(3x-4x)+(6-2)[/tex]
i.e. [tex]f(x)+g(x)=-x+4[/tex]
Thus, the sum of the functions i.e. [tex]f(x)+g(x)=-x+4[/tex].
-x+4 is the answer.
Step-by-step explanation:
We have given two functions.
f(x) = 3x-2
g(x) = 6-4x
We have to find the addition of given two functions.
f(x)+g(x) = ?
Putting given values in above equation, we have
f(x)+g(x) = (3x-2)+(6-4x)
f(x)+g(x) = 3x-2+6-4x
adding like terms ,we have
f(x)+g(x) = (3-4)x+(6-2)
f(x)+g(x) = (-1)x + (4)
f(x)+g(x) = -x +4 which is the answer.
[tex]f(x)+g(x)=3x-2+6-4x=-x+4[/tex]
f(x) = 3x - 2, g(x) = 6 - 4x
f(x) + g(x) = (3x - 2) + (6 - 4x)
= 3x - 2 + 6 - 4x combine like terms
= (3x - 4x) + (-2 + 6)
= -x + 4
Basically substitute f(x) and g(x) in
3x-2+6-4x
Then simplify
-x+4 = 4-x
The answer is B. 4-x
[tex]f(x)+g(x)=3x-2+6-4x=-x+4[/tex]
hehee
Step-by-step explanation:
Idk
N0 (f o g) x = 3x.
Step-by-step explanation:
If they are inverses of each other the f o g will equal x.
f o g = 2(3x +3/ (4x - 2) + 3 / 4(3x + 3)/(4x - 2) - 3)
= 2(3x + 3)+ 3(4x - 2) 4x - 2
*
4x - 2 4(3x + 3) - 3(4x - 2)
6x + 12x
=
12 - 6
= 3x.
So they are not inverses.
D is the right answer