Basic algebra equation. first set up your equation: [tex]9 \times 2x + 4 = 72[/tex]divide out 9.[tex]2x + 4 = 8[/tex]and now you are left with 2x + 4 = 8.
the following points can be visualized easily from the graph
there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote
Basic algebra equation. first set up your equation: [tex]9 \times 2x + 4 = 72[/tex]divide out 9.[tex]2x + 4 = 8[/tex]and now you are left with 2x + 4 = 8.
sin²θ
Step-by-step explanation:
Using the trigonometric identities
sin²x + cos²x = 1 ⇒ cos²x = 1 - sin²x
cotx = [tex]\frac{cosx}{sinx}[/tex]
Given
[tex]\frac{1-sin^20}{cot^20}[/tex]
= [tex]\frac{cos^20}{\frac{cos^20}{sin^20} }[/tex]
= cos²θ × [tex]\frac{sin^20}{cos^20}[/tex] ( cancel the cos²θ )
= sin²θ
both graphs increase on their domain
neither graph has a y-intercept
step-by-step explanation:
the following points can be visualized easily from the graph
there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote