2. Bob bought 24 hockey tickets for $83. Adult tickets cost $5.50 and child tickets cost $2.00. How many child tickets did he buy?

2. Bob bought 24 hockey tickets for $83. Adult tickets cost $5.50 and child tickets cost $2.00. How many child tickets did he buy?

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  1. that's so nice of bob, sadly there is no question here but I'm assuming you want the price of each hockey stick now I'm not the greatest at math but I'm pretty sure I know how to get such answer simple divide the 2 numbers creating the answer as $3.45 I'm pretty sure

  2. [tex]x-\ number\ of\ adult\ tickets\\\\
y-\ number\ of\ children\ tickets\\\\
x+y=24\ \ \ \ | x=24-y\\\\
x*5,5+2*y=83\\\\
5,5(24-y)+2y=83\\\\132-5,5y+2y=83\\\\
132-3,5y=83\ \ \ \ | subtract\ 132\\\\
-3,5y=-49\ \ \ | divide\ by\ -3,5\\\\y=14\\\\
x=10\\\\
He\ bought\ 10\ adult\ tickets\ and\ 14\ children\ tickets.
[/tex]

  3. worked it out is correct your answers are there

    Step-by-step explanation:

    there are your answers

    [tex]2. Bob bought 24 hockey tickets for $83. Adult tickets cost $5.50 and child tickets cost $2.00. How[/tex]

  4. 14

    Step-by-step explanation:

    This can be solved by writing 2 equations and solving simultaneously.

    Let number of Adult tickets be A, and number of child tickets be C.

    "Bob bought 24 hockey tickets":

    [tex]A+C=24[/tex]

    "Adult tickets cost $5.50, and child tickets cost $2.00...Bob bought 24 hockey tickets for $83":

    [tex]5.5A+2C=83[/tex]

    Now we can solve the first equation for A and substitute in 2nd equation and get the value of C.

    A + C = 24

    A = 24 - C

    Now,

    5.5 A + 2 C = 83

    5.5 (24 - C) + 2C = 83

    132 - 5.5C + 2C = 83

    -3.5 C = 83 - 132

    -3.5C = - 49

    C = 14

    Hence, Bob bought 14 child tickets

  5. Step-by-step explanation:

    a + c = 24a = 24 - c

    5.5a + 2c = 83

    5.5(24 - c) + 2c = 83

    132 - 5.5c + 2c = 83

    -5.5c + 2c = 83 - 132

    -3.5c = - 49

    c = -49 / -3.5

    c = 14 < 14 child tickets

    a + c = 24

    a + 14 = 24

    a = 24 - 14

    a = 10 and 10 adult tickets

  6. [tex]x-\ number\ of\ adult\ tickets\\\\&#10;y-\ number\ of\ children\ tickets\\\\&#10;x+y=24\ \ \ \ | x=24-y\\\\&#10;x*5,5+2*y=83\\\\&#10;5,5(24-y)+2y=83\\\\132-5,5y+2y=83\\\\&#10;132-3,5y=83\ \ \ \ | subtract\ 132\\\\&#10;-3,5y=-49\ \ \ | divide\ by\ -3,5\\\\y=14\\\\&#10;x=10\\\\&#10;He\ bought\ 10\ adult\ tickets\ and\ 14\ children\ tickets.&#10;[/tex]

  7. Adult X = 10

    Child Y = 14

    I got this from a pdf i found

    [tex]Bob bought 24 hockey tickets for $83. Adult tickets cost 5.50 and child tickets cost 2.00. How many[/tex]

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