# 2. Bob bought 24 hockey tickets for $83. Adult tickets cost$5.50 and child tickets cost $2.00. How many child tickets did he buy? 2. Bob bought 24 hockey tickets for$83. Adult tickets cost $5.50 and child tickets cost$2.00. How many child tickets did he buy?

## This Post Has 10 Comments

1. dannmend123 says:

that's so nice of bob, sadly there is no question here but I'm assuming you want the price of each hockey stick now I'm not the greatest at math but I'm pretty sure I know how to get such answer simple divide the 2 numbers creating the answer as $3.45 I'm pretty sure 2. pearlvldz says: 83X24=1992 5.50+2.00=7.5 1992/7.5=265.6 3. rylee338 says: $x-\ number\ of\ adult\ tickets\\\\&10;y-\ number\ of\ children\ tickets\\\\&10;x+y=24\ \ \ \ | x=24-y\\\\&10;x*5,5+2*y=83\\\\&10;5,5(24-y)+2y=83\\\\132-5,5y+2y=83\\\\&10;132-3,5y=83\ \ \ \ | subtract\ 132\\\\&10;-3,5y=-49\ \ \ | divide\ by\ -3,5\\\\y=14\\\\&10;x=10\\\\&10;He\ bought\ 10\ adult\ tickets\ and\ 14\ children\ tickets.&10;$ 4. tusharchandler124 says: worked it out is correct your answers are there Step-by-step explanation: there are your answers $2. Bob bought 24 hockey tickets for 83. Adult tickets cost 5.50 and child tickets cost 2.00. How$ 5. keaton846 says: 14 Step-by-step explanation: This can be solved by writing 2 equations and solving simultaneously. Let number of Adult tickets be A, and number of child tickets be C. "Bob bought 24 hockey tickets": $A+C=24$ "Adult tickets cost$5.50, and child tickets cost $2.00...Bob bought 24 hockey tickets for$83":

$5.5A+2C=83$

Now we can solve the first equation for A and substitute in 2nd equation and get the value of C.

A + C = 24

A = 24 - C

Now,

5.5 A + 2 C = 83

5.5 (24 - C) + 2C = 83

132 - 5.5C + 2C = 83

-3.5 C = 83 - 132

-3.5C = - 49

C = 14

Hence, Bob bought 14 child tickets

6. kgonzalez200061 says:

Step-by-step explanation:

a + c = 24a = 24 - c

5.5a + 2c = 83

5.5(24 - c) + 2c = 83

132 - 5.5c + 2c = 83

-5.5c + 2c = 83 - 132

-3.5c = - 49

c = -49 / -3.5

c = 14 < 14 child tickets

a + c = 24

a + 14 = 24

a = 24 - 14

a = 10 and 10 adult tickets

7. sniron says:

He bought 10 adult tickets and 14 child tickets

8. InfinityVicky says:

$x-\ number\ of\ adult\ tickets\\\\&10;y-\ number\ of\ children\ tickets\\\\&10;x+y=24\ \ \ \ | x=24-y\\\\&10;x*5,5+2*y=83\\\\&10;5,5(24-y)+2y=83\\\\132-5,5y+2y=83\\\\&10;132-3,5y=83\ \ \ \ | subtract\ 132\\\\&10;-3,5y=-49\ \ \ | divide\ by\ -3,5\\\\y=14\\\\&10;x=10\\\\&10;He\ bought\ 10\ adult\ tickets\ and\ 14\ children\ tickets.&10;$

9. chandranewlon says:

i think the answer is \$3.45

Step-by-step explanation:

just had to divide the two numbers

10. athenawalcroff says:

Child Y = 14

I got this from a pdf i found

$Bob bought 24 hockey tickets for 83. Adult tickets cost 5.50 and child tickets cost 2.00. How many$