(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth? 5.7 units

6.3 units

1 unit

4 units

Skip to content# (2) Using the distance formula, d = √(x2 – x1)2 + (y2 – y1)2, what is the distance between point (-2, 2) and point (4, 4) rounded

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(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth? 5.7 units

6.3 units

1 unit

4 units

a

Step-by-step explanation:

I don’t really understand this question

Q1) 3

Q2) 4

Q3) 4

Q4) 3

Q5) 3

Q6) 3

Exp:3x²-2-8x-1=0

3x²-8x-3=0

(x-3)(3x+1)=0

x=3 or -1/3

Q7) 4

Q8) ??

The difference between 4 5/7 and 1 3/4 is 83/28 or 2 27/28

Step-by-step explanation:

First, to make it easier to subtract, let's change these numbers to improper fractions.

4 5/7 = 33/7

1 3/4 = 7/4

Now, we have to find the LCM (least common multiple) between 4 and 7.

4- 4, 8, 12, 16, 20, 24, 28, 32

7- 7, 14, 21, 28, 35, 42, 49

As you can see, the LCM is 28. So, lets change these fractions to have a denominator of 28.

33*4/ 7*4 = 132/ 28

7*7/ 4*7 = 49/ 28

>>132 - 49 = 83

So, the difference between 4 5/7 and 1 3/4 is 83/28 or 2 27/28

1. 4

2.4

3.3

4.2

5.2

6.what after the plus

7.3

8.

the answer is going to be

A

Answer with explanation:

1.

Let a, and b be two numbers between 20 and 5 , which is in geometric progression.

So,the series is as Follows =20 , a, b, 5

Common ratio

[tex]=\frac{\text{Second term}}{\text{First term}}[/tex]

[tex]\frac{20}{a}=\frac{a}{b}=\frac{b}{5}\\\\b^2=5 a---(1)\\\\a^2=20 b\\\\\frac{b^4}{25}=20 b-----\text{Using 1}\\\\b^3=500\\\\b=(500)^{\frac{1}{3}}\\\\b=5\times (4)^{\frac{1}{3}}\\\\5a=25\times (4)^{\frac{2}{3}}\\\\a=5\times (4)^{\frac{2}{3}}[/tex]

2.

44 -32-3

=12-3

=9

3.

⇒Sin (2.4)=Sin(2+0.4)

⇒Sin 2 ×Cos (0.4)+Cos 2 × Sin (0.4)

⇒Sin (A+B)=Sin A×Cos B+Cos A×Sin B

2

1

2

3

3

2

4

2

i am n't sure 🙂

I believe it is all real numbers, but get an approval from someone else first

Answer is in the photo. I can't attach it here, but I've uploaded it to a file hosting. link below! Good Luck!

cutt.ly/XzW3SUN