# (2) Using the distance formula, d = √(x2 – x1)2 + (y2 – y1)2, what is the distance between point (-2, 2) and point (4, 4) rounded

(2) Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (-2, 2) and point (4, 4) rounded to the nearest tenth? 5.7 units

6.3 units

1 unit

4 units

## This Post Has 10 Comments

1. javink18 says:

a

Step-by-step explanation:

2. princesskhj6932 says:

I don’t really understand this question

3. Kimmie2019 says:

Q1) 3
Q2) 4
Q3) 4
Q4) 3
Q5) 3
Q6) 3
Exp:3x²-2-8x-1=0
3x²-8x-3=0
(x-3)(3x+1)=0
x=3 or -1/3
Q7) 4
Q8) ??

4. soevse says:

The difference between 4 5/7 and 1 3/4 is 83/28 or 2 27/28

Step-by-step explanation:

First, to make it easier to subtract, let's change these numbers to improper fractions.

4 5/7 = 33/7

1 3/4 = 7/4

Now, we have to find the LCM (least common multiple) between 4 and 7.

4- 4, 8, 12, 16, 20, 24, 28, 32

7- 7, 14, 21, 28, 35, 42, 49

As you can see, the LCM is 28. So, lets change these fractions to have a denominator of 28.

33*4/ 7*4 = 132/ 28

7*7/ 4*7 = 49/ 28

>>132 - 49 = 83

So, the difference between 4 5/7 and 1 3/4 is 83/28 or 2 27/28

5. mikego5 says:

1. 4
2.4
3.3
4.2
5.2
6.what after the plus
7.3
8.

6. fardinhaque6113 says:

the answer is going to be

A

7. kgarc1019 says:

1.

Let a, and b be two numbers between 20 and 5 , which is in geometric progression.

So,the series is as Follows =20 , a, b, 5

Common ratio

$=\frac{\text{Second term}}{\text{First term}}$

$\frac{20}{a}=\frac{a}{b}=\frac{b}{5}\\\\b^2=5 a---(1)\\\\a^2=20 b\\\\\frac{b^4}{25}=20 b-----\text{Using 1}\\\\b^3=500\\\\b=(500)^{\frac{1}{3}}\\\\b=5\times (4)^{\frac{1}{3}}\\\\5a=25\times (4)^{\frac{2}{3}}\\\\a=5\times (4)^{\frac{2}{3}}$

2.

44 -32-3

=12-3

=9

3.

⇒Sin (2.4)=Sin(2+0.4)

⇒Sin 2 ×Cos (0.4)+Cos 2 × Sin (0.4)

⇒Sin (A+B)=Sin A×Cos B+Cos A×Sin B

8. bbrogle5154 says:

2
1
2
3
3
2
4
2
i am n't sure 🙂

9. Undrea43 says:

I believe it is all real numbers, but get an approval from someone else first

10. RoyalGurl01 says:

Answer is in the photo. I can't attach it here, but I've uploaded it to a file hosting. link below! Good Luck!

cutt.ly/XzW3SUN