# 2.Which of the following could be sidelengths of a right triangle? Circle all thatapply.A. 12. 16.

2.Which of the following could be side lengths of a right triangle? Circle all that
apply.
A. 12. 16. 20
B. 4.5, 6, 7,5
C. 5. 12. 13
D. 6. 12.14
E. 5.7.10

## This Post Has 10 Comments

1. decapria says:

are yuo high im in middle

Step-by-step explanation:

2. adriandehoyos1p3hpwc says:

A

Step-by-step explanation:

IT IS A

3. bestsisever0 says:

B. 85, 13 and 84, i hope its right.  🙂

Step-by-step explanation:

have a good day

4. 1846252 says:

Step-by-step explanation:

Mark me as brainliest

5. kaylabjoyner4023 says:

D

Step-by-step explanation:

6. lusciousl says:

D 12,16,20

Step-by-step explanation:

The Pythagora's Theorem

On a right triangle with side lengths of a,b, and c, being c the hypotenuse, of the longest side, it follows that:

$a^2+b^2=c^2$

The set {a,b,c} is often called a Pythagorean Triple.

Testing every option:

A

$5^2+8^2=10^2$

$25+64 = 100$

89 = 100

Since equality is false, 5,8,10 are not the side lengths of a right triangle.

B

$3^2+5^2=7^2$

$9+25 = 49$

34 = 49

Since equality is false, 3,5,7 are not the side lengths of a right triangle.

C

$6^2+11^2=13^2$

$36+121 = 169$

157 = 169

Since equality is false, 6,11,13 are not the side lengths of a right triangle.

D

$12^2+16^2=20^2$

$144+256 = 400$

400 = 400

Since equality is true, 12,16,20 could be the side lengths of a right triangle.

D 12,16,20

7. jaylahlove77 says:

B. 1.8, 2.4, 3

Step-by-step explanation:

You can make use of pythagore to prove each of the given options and you'll see that B is the correct

A) $\sqrt{0.1^{2}+0.2^{2}}=0.22$

B) $\sqrt{1.8^{2}+2.4^{2}}=3$

C)$\sqrt{3^{2}+8^{2}}=8.54$

D)$\sqrt{5^{2}+7^{2}}=8.6$

8. krojas015 says:

1. A

2.C

3.C

Step-by-step explanation:

9. renee9913 says:

Answers are c, a, and c

10. svlext says:

Choice D

Step-by-step explanation:

If you check each one plugging in your info into this you can get $a^{2} +b^{2} =c^{2}$ that 12² + 16² will equal 400 which is the same as 20².