2.Which of the following could be side lengths of a right triangle? Circle all that

apply.

A. 12. 16. 20

B. 4.5, 6, 7,5

C. 5. 12. 13

D. 6. 12.14

E. 5.7.10

Skip to content# 2.Which of the following could be sidelengths of a right triangle? Circle all thatapply.A. 12. 16.

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2.Which of the following could be side lengths of a right triangle? Circle all that

apply.

A. 12. 16. 20

B. 4.5, 6, 7,5

C. 5. 12. 13

D. 6. 12.14

E. 5.7.10

are yuo high im in middle

Step-by-step explanation:

A

Step-by-step explanation:

IT IS A

B. 85, 13 and 84, i hope its right. 🙂

Step-by-step explanation:

have a good day

B is the correct answer...

Step-by-step explanation:

Mark me as brainliest

D

Step-by-step explanation:

D 12,16,20

Step-by-step explanation:

The Pythagora's Theorem

On a right triangle with side lengths of a,b, and c, being c the hypotenuse, of the longest side, it follows that:

[tex]a^2+b^2=c^2[/tex]

The set {a,b,c} is often called a Pythagorean Triple.

Testing every option:

A

[tex]5^2+8^2=10^2[/tex]

[tex]25+64 = 100[/tex]

89 = 100

Since equality is false, 5,8,10 are not the side lengths of a right triangle.

B

[tex]3^2+5^2=7^2[/tex]

[tex]9+25 = 49[/tex]

34 = 49

Since equality is false, 3,5,7 are not the side lengths of a right triangle.

C

[tex]6^2+11^2=13^2[/tex]

[tex]36+121 = 169[/tex]

157 = 169

Since equality is false, 6,11,13 are not the side lengths of a right triangle.

D

[tex]12^2+16^2=20^2[/tex]

[tex]144+256 = 400[/tex]

400 = 400

Since equality is true, 12,16,20 could be the side lengths of a right triangle.

D 12,16,20

B. 1.8, 2.4, 3

Step-by-step explanation:

You can make use of pythagore to prove each of the given options and you'll see that B is the correct

A) [tex]\sqrt{0.1^{2}+0.2^{2}}=0.22[/tex]

B) [tex]\sqrt{1.8^{2}+2.4^{2}}=3[/tex]

C)[tex]\sqrt{3^{2}+8^{2}}=8.54[/tex]

D)[tex]\sqrt{5^{2}+7^{2}}=8.6[/tex]

1. A

2.C

3.C

Step-by-step explanation:

Answers are c, a, and c

Choice D

Step-by-step explanation:

If you check each one plugging in your info into this you can get [tex]a^{2} +b^{2} =c^{2}[/tex] that 12² + 16² will equal 400 which is the same as 20².