36 students signed up to volunteer for a race two or three equal groups of students and each group had a different task how many students were in each group
36 students signed up to volunteer for a race two or three equal groups of students and each group had a different task how many students were in each group
d. 24+-0.114
step-by-step explanation:
the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;
sample mean = 24
standard deviation, σ = 0.4
sample size , n = 49
the confidence interval for a population mean is calculated using the formula;
sample mean ± z-score*(σ/sqrt(n))
the z-score associated with a 95% confidence interval, from the standard normal tables, is;
1.96
substituting these values into the formula;
24 ± 1.96*(0.4/7)
= 24 ± 0.112
from the alternatives given, choice d is closest to the above expression;
I two groups are formed: 18 students
If 3 groups are formed: 12 students
Step-by-step explanation:
We will answer this problem based on two occurrences:
1. The students chose to form only two groups:
If the students chose to form only two groups, the number of students in each group will be got by dividing the total number of students by 2. this will be 36/2 = 18. Therefore, there will be 18 students per group if only 2 groups were formed.
2. The students chose to form three groups:
If the students chose to form three groups, we will divide the total number of students by 3. this will be 36/3 = 12. Therefore, there will be 12 students per group if only 3 groups were formed.
a
step-by-step explanation: