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(7) Besides academic achievement, art and music also help to develop children’s motor skills. (8) Activities such as playing

Posted on October 23, 2021 By Pinklover2002 2 Comments on (7) Besides academic achievement, art and music also help to develop children’s motor skills. (8) Activities such as playing

(7) Besides academic achievement, art and music also help to develop children's motor skills. (8) Activities such as playing an instrument or making a painting using a paintbrush or a crayon help to develop a child's fine motor skills.

(i have only pasted pgh 3, if need more info tell me)

Which evidence would be best to add to paragraph 3 to support the claim that music develops fine motor skills?
A.
For example, playing the cello requires strong fingers to hold down the strings.
B.
For example, playing the trumpet requires strong diaphragm muscles to enable controlled exhalation.
C.
For example, playing the violin requires precise finger placement to ensure that notes are in tune.
D.
For example, playing the bass requires students to stand for long periods at a time.

Will give brainliest? answer correctly not improper please or will get deleted

English

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Comments (2) on “(7) Besides academic achievement, art and music also help to develop children’s motor skills. (8) Activities such as playing”

  1. vinniemccray70 says:
    October 23, 2021 at 7:37 pm

    I believe the answer is letter B. I think this because the trumpet only requires the use of three fingers, so it may be easier to play than woodwind instruments.

    To make a sound, kids blow air through almost closed lips. That can help strengthen the fine motor skills of the mouth.

    The child needs to be able to breathe strongly and with control, in and out, using diaphragm muscles. Doing this will develop the motor skills they would later on need.

    Hope this helped you!

    Reply
  2. ohnoitsabby5431 says:
    October 24, 2021 at 4:28 am

    1) 1.15 mol

    2) M=0.45

    3) 22.5 mL

    4) 6.25 mL

    Explanation:

    1)

    550 mL= 0.55 L

    M= mol solute/ L solution

    mol solute= M * L solution

    mol solute= (2.1 M * 0.55 L )        M=1.15 mol solute

    2)

    155 mL = 0.155 L

    80 g  -> 1 mol NH4NO3

    5.61 g -> x

    x= (5.61 g * 1 mol NH4NO3)/80 g       x= 0.07 mol NH4NO3

    M=(0.07 mol NH4NO3)/0.155 L         M=0.45

    3) M1V1=M2V2

    V1= M2V2/M1

    V1= (0.500 M * 0.225 L)/5.00 M             V1=0.0225 L =22.5 mL

    4) M1V1=M2V2

    V1= M2V2/M1

    V1= (0.25 M * 0.45 L)/ 18.0 M

    V1=6.25 x 10^-3 L = 6.25 mL

    Reply

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