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771. Mr. Bueller gave his Algebra I class a test on statistics. After the test, he presented the following data to hisstudents

Posted on October 22, 2021 By mobete 6 Comments on 771. Mr. Bueller gave his Algebra I class a test on statistics. After the test, he presented the following data to hisstudents

77 1. Mr. Bueller gave his Algebra I class a test on statistics. After the test, he presented the following data to his
students regarding their test scores (scores are in percentages).
Lowest Score: 0
Mean: 74.5
First Quartile: 68
Standard Deviation: 18.5
Median: 77
Third Quartile: 85
Highest Score: 98
The lowest score was calculated as a zero because the student had been absent. Once the student returned to
school, she took the test. Unfortunately, she had been absent for most of the lessons and only scored a 53% which
is still the lowest score. How would replacing the 0% with a 53% affect the statistics? Place a check in the box that
describes the new value.
+
Stays the Same
Increases
Decreases
Mean
Standard Deviation
Median
Interquartile Range


[tex]77 1. Mr. Bueller gave his Algebra I class a test on statistics. After the test, he presented the[/tex]

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Comments (6) on “771. Mr. Bueller gave his Algebra I class a test on statistics. After the test, he presented the following data to hisstudents”

  1. Orabah says:
    October 23, 2021 at 9:11 am

    wait so ur not looking for answers?

    Reply
  2. Expert says:
    October 23, 2021 at 5:14 pm

    answer: your correct answer is b. d.

    step-by-step explanation:

    Reply
  3. kyzerlinda says:
    October 23, 2021 at 7:00 pm

    Answers:

    A. Ms. Dobson’s class has a smaller range of scores;

    B. The district has a greater interquartile range; and

    C. Fifteen is an outlier for the district’s scores.

    Explanation:

    The scores for Ms. Dobson's class go from the lowest of 40 to the highest of 95; this is a range of 95-40 = 55.  The scores for the district go from the lowest of 15 to the highest of 100; this is a range of 100-15 = 85.  Ms. Dobson's class has a smaller range of scores.

    The interquartile range (IQR) is found by subtracting Q3, the third quartile, and Q1, the first quartile.

    For Ms. Dobson's class, Q1 is 70 and Q3 is 80; this makes the IQR 80-70 = 10.  For the district, Q1 is 55 and Q3 is 75; this makes the IQR 75-55 = 20.  The district has a greater interquartile range.

    An outlier is any value that is less than 1.5 times the interquartile range below Q1 or greater than 1.5 times the interquartile range above Q3.

    For the district, Q1 is 55 and the IQR is 20; any outlier would be less than

    55-1.5(20) = 55-30 = 25.  15 is less than 25, so it would be an outlier.

    For the district, Q3 is 75 and the IQR is 20; any outlier would be greater than 75+1.5(20) = 75+30 = 105; there are no values in the district's scores this high or more; 100 is not an outlier for this set.

    Ms. Dobson's class had scores that were overall higher than the district.  While the district had a few that were higher, the scores for Ms. Dobson's class were clustered higher than those of the district.

    Reply
  4. michellemaricioxbyk0 says:
    October 23, 2021 at 8:52 pm

    A)Ms. Dobson’s class has a smaller range of scores.

    B)The district has a greater interquartile range.

    C)Fifteen is an outlier for the district’s scores.

    Step-by-step explanation:

    Just took the test

    Reply
  5. heastonk9136 says:
    October 23, 2021 at 10:09 pm

    Wait sooo umm can i just use this

    Reply
  6. Expert says:
    October 24, 2021 at 2:03 am

    da freeck kinda math is this just drop out

    step-by-step explanation:

    Reply

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