7th Grade Math

Please help

-7 = 1/3 a

Find the value of a

Skip to content# 7th Grade MathPlease help-7 = 1/3 aFind the value of a

Mathematics ##
Comments (10) on “7th Grade MathPlease help-7 = 1/3 aFind the value of a”

### Leave a Reply Cancel reply

7th Grade Math

Please help

-7 = 1/3 a

Find the value of a

3/8

Step-by-step explanation:

If 1/4 is equaled to 1. This is 1 dived by 4 to get the 1/4.

Then 1.5 would be divided by 4 to get 3/8

3/8th should be your answer

M

Step-by-step explanation:

It's an isosceles triangle so the height bisects the base making two right triangles with legs x/2 and y and hypotenuse √74.

(x/2)² + 7² = (√74)²

x²/4 + 49 = 74

x²/4 = 25

x² = 100

x = 10

C

x = [tex]\frac{57}{2}[/tex]

Step-by-step explanation:

Given

- 19 = - [tex]\frac{2}{3}[/tex] x ( multiply both sides by 3 to clear the fraction )

- 57 = - 2x ( divide both sides by - 2 )

[tex]\frac{-57}{-2}[/tex] = x , that is

x = [tex]\frac{57}{2}[/tex]

C. x=10

Step-by-step explanation:

Using the Pythagorean Theorem, you know that 7²+s²=(√74)², I'm using the variable s so we don't get confused with the other x variable.

Square root the numbers you can: 49+s²=74

Subtract 49 from both sides of the equation to isolate the variable: s²=25

Square root both sides to find the value of s: s=5

S is half of the value of x, so double s to get your answer, 10

[tex]\huge\boxed{r=\dfrac{57}{5}\to r=11\dfrac{2}{5}\to r=11.4}[/tex]

Step-by-step explanation:

[tex]19=\dfrac{5}{3}r\to\dfrac{5}{3}r=19\qquad|\text{multiply both sides by 3}\\\\3\!\!\!\!\diagup\cdot\dfrac{5}{3\!\!\!\!\diagup}r=19\cdot3\\\\5r=57\qquad|\text{divide both sides by 5}\\\\\dfrac{5r}{5}=\dfrac{57}{5}\\\\r=\dfrac{57}{5}\to r=11\dfrac{2}{5}\to r=11.4[/tex]

4.8

Step-by-step explanation:

-19=-2/3x

3*-19=-2x

-57=-2x

-57/-2=x

57/2=x

x=28.5

Step-by-step explanation:

B

Step-by-step explanation: