# 8 ( x+ 7 ) = – 24 solve for x

8 ( x+ 7 ) = - 24 solve for x

## This Post Has 10 Comments

1. niyah2224 says:

x=-10

Step-by-step explanation: im built different

2. Expert says:

3. mxrvin7383 says:

21

Step-by-step explanation:

4. Expert says:

just remember to use pemdas:

parentheses

expressions

multiplication

division

subtraction

5. preciousharrington13 says:

The answers are as follows:

TrueFalseFalseFalseFalse

Step-by-step explanation:

Let us look at the statements one by one

1. The additive inverse of 10 is -10.

The additive inverse of a number is the opposite of a number with respect to sign.

The sum of a number and its additive inverse is zero.

$10+(-10) = 10-10 = 0$

This statement is true.

2. Zero is a positive number.

Zero is neither a positive number nor a negative number. It is only used as reference to decide whether a number is positive or negative.

This statement is false.

3. To divide two unlike signs, the quotient is always positive.

When two unlike signs are divided, the answer will be negative as division involves multiplication, and multiplication of two numbers with unlike signs will always be negative.

This statement is false.

4. Commutative Property states that:

a + (b + c ) = (a + b ) + c

Commutative property deals with two numbers or variables only. The property with three numbers or varibales is associative property. Hence,

This statement is false.

5. One is the identity element of for addition.

Additive identity is a number that when added to a number x, the result will always be x. Zero is additive identity.

Hence,

This statement is false.

The answers are as follows:

TrueFalseFalseFalseFalse

6. izzy488 says:

See explaination

Explanation:

This function reverses the position

of the consonants keeping the

position of vowel constant.

Parameters:

data : type(str)

The string on which operation

needs to be performed

start : type(int)

Starting index of the string

end : type(int)

Ending index of the string

"""

def consonantReverse(data, start = 0, end = None):

 By default user will psas the data only.

End will be none which will be set to length of string - 1

if(end == None):

return consonantReverse(data, 0, len(data)-1)

 return as this is invalid

if(start >= end):

return data

split the data into list

if type(data)== str:

data = list(data)

 initialize index1 and index2

index1 = len(data)

index2 = -1

find out the first index from beggining

 where consonant is present

for i in range(start, end+1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index1 = i

break

find out the index from the end

 where consonant is present

for i in range(end, start-1, -1):

if(data[i] not in ['a','e','i','o','u','A','E','I','O','U']):

index2 = i

break

return as this is not valid case

if(index1 >= index2):

return ''.join(data)

 swap the data in the two index

data[index1], data[index2] = data[index2], data[index1]

call the function recursively

data = consonantReverse(data, index1+1, index2-1)

 if it is a list, join the list into string

if(type(data) == list):

return ''.join(data)

otherwise return the data

else:

return data

7. AbigailHaylei says:

welp

step-by-step explanation:

8. amanda1717 says:

wt.f is this

Step-by-step explanation:

9. christhegreat1 says: