∠a and ∠b are vertical angles with m∠a = x and m∠b = 4x - 30. what is m∠a?

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∠a and ∠b are vertical angles with m∠a = x and m∠b = 4x - 30. what is m∠a?

answer: howdy

step-by-step explanation:

answer:

g

step-by-step explanation:

[tex]x = 4x -30[/tex]

We can solve for x subtracting x on both sides:

[tex]x-x= 4x-x-30[/tex]

And then we can add 30 in both sides:

[tex]30= 3x[/tex]

And dividing both sides by 3 we got:

[tex]x = 10[/tex]

Step-by-step explanation:

For this case we know the measure of two angles:

[tex]m <A = x[/tex]

[tex]m<B = 4x-30[/tex]

And we know that both angles are vertical and by definition vertical angles are the angles opposite each other when two lines cross.

For this case since both angles are vertical we have the property that:

[tex]m<A = m<B[/tex]

And replacing what we got we have:

[tex]x = 4x -30[/tex]

We can solve for x subtracting x on both sides:

[tex]x-x= 4x-x-30[/tex]

And then we can add 30 in both sides:

[tex]30= 3x[/tex]

And dividing both sides by 3 we got:

[tex]x = 10[/tex]

4x-30=180

180-30

4x=150

150/4

37.5

x=37.5

we know that

Vertical Angles are the angles opposite each other when two lines cross. They are always congruent to one another

in this problem

∠A and ∠B are vertical angles

so

∠A=∠B

we have

∠A=[tex]x\°[/tex]

∠B=[tex](5x-80)\°[/tex]

equate angle A and angle B

[tex]x=5x-80[/tex]

solve for x

[tex]5x-x=80[/tex]

[tex]4x=80[/tex]

[tex]x=20\°[/tex]

therefore

the answer is

the measure of angle A is [tex]20\°[/tex]

we know that

Vertical angles are congruent angles opposite each other where two lines cross

so

in this problem

m∠A=m∠B

so

substitute the values

[tex]x=3x-60\\3x-x=60\\2x=60\\x=60/2\\x=30\°[/tex]

therefore

the answer is

The measure of angle A is [tex]30\°[/tex]

m∠A=30°

Step-by-step explanation:

we know that

Vertical Angles are the angles opposite each other when two lines cross.

Vertical angles always are congruent

In this problem

m∠A=m∠B ----> by vertical angles

we have

m∠A=x

m∠B=3x-60

substitute

[tex]3x-60=x[/tex]

Solve for x

[tex]3x-x=60[/tex]

[tex]2x=60[/tex]

[tex]x=30[/tex]

therefore

m∠A=30°

m∠A=10°

Step-by-step explanation:

we know that

Vertical angles are the angles opposite each other when two lines cross. The angles are congruent.

so

In this problem we have

m∠A=m∠B

substitute the given values

[tex]x=4x-30[/tex]

Solve for x

[tex]4x-x=30\\3x=30\\x=10[/tex]

Find the measure of angle A

m∠A=x

substitute the value of x

m∠A=10°

Angle A would be anything that Angle B is. If the angles are vertical then they are always congruent.

20 degrees

vertical angles are equal, so 5x-80=x

solve for x and you get 20

l.jnl.j/n.m,lm,

step-by-step explanation:

∠A and ∠B are vertical angles

so

∠A =∠B

x = 4x - 30

4x - x = 30

3x = 30

x = 10

m<A= x = 10

answer

m<A = 10