# A, b, c, and d have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. which sentence

A, b, c, and d have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. which sentence about the points is true?
a: a, b, c, and d lie on the same line.
b: ab and cd are perpendicular lines.
c: ab and cd are parallel lines.
d: ab and cd are intersecting lines but are not perpendicular.
e: ac and bd are parallel lines.

## This Post Has 10 Comments

1. danielacortevpe3i66 says:

Hmm... maybe it's E? I'm not 100% sure.

2. Isaiahtate053 says:

Option B is correct.

Step-by-step explanation:

To check if the lines are parallel or perpendicular, we need to find the slope of lines AB and CD

A=(-8,1), B= (-2,4), C= (-3, -1), and D= (-6,5)

Slope of AB = y₂-y₁/x₂-x₁

Slope of AB = 4-1/-2-(-8)

Slope of AB = 3/-2+8

Slope of AB = 3/6

Slope of AB = 1/2

Slope of CD = y₂-y₁/x₂-x₁

Slope of CD = 5+1/-6-(-3)

Slope of CD = 6/-6+3

Slope of CD = 6/-3

Slope of CD = -2

Lines are parallel if Slope of AB = Slope of CD

Lines are perpendicular if Slope of Ab = -1/Slope of CD

So, Slope of AB = 1/2

Slope of CD = -2

So, LINE AB AND LINE CD ARE PERPENDICULAR

Option B is correct.

3. s237200 says:

AB and CD are intersecting lines but are not perpendicular.

See attached image.

Step-by-step explanation:

4. laceytoyne72 says:

D

Step-by-step explanation:

A helpful tip is go to desmos.com. That's how I got this answer.

5. sydneyharding36191 says:

E. As said by another user is the incorrect answer.

B. Is the correct answer- Lines AB and CD are perpendicular. I've included a diagram as proof.

$A, b, c, and d have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. which sen$

6. notmclovinyou says:

The correct answer to that question is that they are perpendicular lines.

7. rosas8 says:

Coordinates of A, B, C, and D are  (-8, 1), (-2, 4), (-3, -1), and (-6, 5).

Plotting the points on two dimensional plane

1. You will find that, the four points, A , B , C and D do not lie on the dame Line.

$\text{Slope of AB}=\frac{4-1}{-2+8}=\frac{3}{6}=\frac{1}{2}\\\\\text{Slope of CB}=\frac{4+1}{-2+3}=\frac{5}{1}=5\\\\\text{Slope of CD}=\frac{5+1}{-6+3}=\frac{6}{-3}=-2\\\\\text{Slope of AD}=\frac{5-1}{-6+8}=\frac{4}{2}=2\\\\\text{Slope of BD}=\frac{5-4}{-6+2}=\frac{1}{-4}=\frac{-1}{4}\\\\\text{Slope of AC}=\frac{-1-1}{-3+8}=\frac{-2}{5}$

→→None of the two lines are Parallel nor they are perpendicular,because neither product of slopes of two lines is equal to ,-1, nor the slope of two lines are equal.

It means they are Intersecting Lines .

Option D:⇒ And are intersecting lines but are not perpendicular.

$A, b, c, and d have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. which sen$

8. SugaAndKookie22 says:

9. briizy says:

$A, b, c, and d have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. which sen$

10. jazzwok says:

The Coordinates of point ,  A, B, C, and D are (-8, 1), (-2, 4), (-3, -1), and (-6, 5).

Slope between two points is given by

$(x_{1},y_{1}),\text{and},(x_{2},y_{2}) \text{is},=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text{Slope of AB}=\frac{4-1}{-2+8}\\\\=\frac{3}{6}=\frac{1}{2}\\\\\text{Slope of CB}=\frac{4+1}{-2+3}\\\\=\frac{5}{1}=5\\\\\text{Slope of CD}=\frac{5+1}{-6+3}\\\\=\frac{6}{-3}=-2\\\\\text{Slope of AD}=\frac{5-1}{-6+8}\\\\=\frac{4}{2}=2\\\\\text{Slope of DB}=\frac{4-5}{-2+6}\\\\=\frac{-1}{4}\\\\\text{Slope of AC}=\frac{1+1}{-8+3}\\\\=\frac{2}{5}$

Coming at the Options

1. Option 1 , is not true, because points, A, B, C and D are not collinear.

2. Slope of AB × Slope of CD

$=\frac{1}{2} \times -2\\\\-1$

So, lines AB and CD are Perpendicular.

3. None, of the lines are parallel, as the slopes of two distinct lines are not equal.

4. None of the lines are parallel, So, all of the lines, AB, BC, CD, DA,AC, and B D are Intersecting.

$A, b, c, and d have the coordinates (-8, 1), (-2, 4), (-3, -1), and (-6, 5), respectively. which sen$