A bullet is shot straight up into the air from ground level. It reaches a maximum height at h = 739 m.

[tex]A bullet is shot straight up into the air from ground level. It reaches a maximum height at h = 7[/tex]

Skip to content# A bullet is shot straight up into the air from ground level. It reaches a maximumheight at h = 739 m.

##
This Post Has 4 Comments

### Leave a Reply

A bullet is shot straight up into the air from ground level. It reaches a maximum height at h = 739 m.

[tex]A bullet is shot straight up into the air from ground level. It reaches a maximum height at h = 7[/tex]

A) acceleration. this seems to be the one that makes sense.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

[tex]x(t)=ax(x-6)[/tex]

where [tex]a[/tex] is unknown. because the position is parabolic, there is symmetry about the midpoint at [tex]t=3[/tex], and we know that

[tex]x(3)=10\implies -9a=10\implies a=-\dfrac{10}9[/tex]

so that the position function is

[tex]x(t)=-\dfrac{10}9x(x-6)[/tex]

which means the velocity is

[tex]v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9[/tex]

then the total distance traveled is

[tex]\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20[/tex]

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at [tex]x=0[/tex] and ends at [tex]x=0[/tex], so its displacement is 0.

[tex]Решите , пожалуйста, номер 119 срочно[/tex]

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

come closer and become far apart and become steam/gas