A cannon is placed on high ground 24 ft above a target that is 1000 ft away horizontally. It fires a

A cannon is placed on high ground 24 ft above a target that is 1000 ft away horizontally. It fires a projectile upward at a 45° angle with an initial speed of to ft/s. Whаt vаluе оf tip is necessary for the projectile to hit the target? The acceleration due to gravity is g = 32 ft/s2.
a. vo = (500)^1/2
b. vo = 150
с. vo = 100(2)^1/2
d. vo = 250
e. vo = 125(2)^1/2

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This Post Has 3 Comments

  1. yor answer is 7/6 times 5

    step-by-step explanation:

    [tex]Which of the following products is equivalent to the quotient 1 1/6 • 1/5[/tex]

  2. D. vo = 125(2)^1/2

    Step-by-step explanation:

    Range of a projectile is the defined as the distance covered in the horizontal direction.

    Range = U²sin2θ/g

    U is the speed of the object

    θ is the angle of launch

    g is the acceleration due to gravity

    If the target is 1000 ft away horizontally, range = 1000ft

    θ = 45°

    g = 32ft/s²

    1000 = U²sin2(45°)/32

    32000 =U²sin90°

    32000 = U²

    U = √32000

    U = 125√2 m/s

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