A circuit can only light up a lightbulb if there is a path for electricity to travel from one end of the energy source to the other end.
A circuit can only light up a lightbulb if there is a path for electricity to travel from one end of the energy source to the other end.
Continuous
Explanation:
A circuit can only light up a lightbulb if there is a continuous path for electricity to travel from one end of the energy source to the other end.
To this equation you must first ask yourself how to do it. Now in order to finish just do it
You really like to squeeze all you can out of your points, don't you !
This question should really be reported for being too complex. But I'm such a nerd for electrical stuff, I'm gonna answer it anyway.
12 ohms (C)
7.55 ohms (B)
Vero has the probes of her DMM swapped. (D)
Resistance (D)
Tolerance (C)
70 ohms (D)
The meter will read zero ohms. (D)
0.06 A (60 mA) (C)
4,000 watts (A)
High-current power transformer (A)
W / I² (B)
Continuity test (C). She should do the short circuit test too (A). If the motor winding failed because it melted into a blob of copper during a few seconds of extreme over-current, it would pass a Continuity test just fine and Jen would not know that it had failed.
Personally, I use a high-voltage probe when I'm measuring ANY voltage. I've been zapped. No, I mean I've been zapped GOOD ! I'm an Electrical Engineer, so I know enough to be afraid of the stuff.
1A of current flows due to an applied voltage of 1V. (C)
Step the voltage down and read the stepped-down voltage, multiplying it by the step factor. (D)
The circuit is most likely energized ... the wrong way to measure a resistor in a circuit, and you can easily damage your meter by doing that. (C)
It's also possible that the resistor might have taken an extreme zap and permanently changed its value. (That could be one reason why you're measuring it.) (D)
If I don't get a 'Brainliest' for this one, then there's no justice in the world.
As a little extra side-problem in Math, I just wanna mention that my efforts have been rewarded with a generous bounty of 0.3125 point per answer. Shame on me !
continuios
Explanation:
If one bulb goes out then all the others won't light up because electricity will be cut off. It's a disadvantage because in a parallel circuit if one bulb burns out all the others will still be on because they won't be affected. I hope I've helped you ☺
Explanation:
A path for electricity is a circuit.hope it helps.stay safe healthy and happy.
1A
2B
3C
4D
5D
6C
7A
8B
9C
10A
11B
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A path for electricity is current
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