A conference consists of 5 sessions: A, B, C, D, and E. Here are the costs of the sessions.Session A: $50Session B: $50Session C: $100Session

A conference consists of 5 sessions: A, B, C, D, and E. Here are the costs of the sessions. Session A: $50
Session B: $50
Session C: $100
Session D: $150
Session E: $200

A participant plans to attend 3 sessions. Here is a list of all possible samples of size 3 sessions from this population of 5 sessions: ABC, ABD, ABE, ACD, ACE, ADE, BCD, BCE, BDE, and CDE. If sessions A, B, and C are selected, what is the sample minimum session cost?

$50
$66.67
$100
$200

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This Post Has 9 Comments

  1. [tex]\begin\\\begin{tabular}{|l|l|l|}No&Sample&Median\\01&58,42,37 &42\\02&58,42,34&42\\03&58,42,23& 42\\04&37,34,23 & 34\\05&58,37,34 & 37\\06&58,37,23 & 37\\07&58,34,23 &34\\08&42,37,34 &37\\09&42,37,23 &37\\10&42,34,23 &34\end[/tex]

    Step-by-step explanation:

    From the question we are told that

    5 samples(23 34 37 42 58)

    To select 3 random sample

    a) Generally to find all 10 possible outcomes and there median we make a table

    Therefore

    L1

    58,42,37  Median=42

    L2

    58,42,34  Median=42

    L3

    58,42,23  Median=42

    L4

    37,34,23  Median=34

    L5

    58,37,34  Median=37

    L6

    58,37,23  Median=37

    L7

    58,34,23  Median=34

    L8

    42,37,34  Median=37

    L9

    42,37,23  Median=37

    L10

    42,34,23  Median=34

    [tex]\begin\\\begin{tabular}{|l|l|l|}No&Sample&Median\\01&58,42,37 &42\\02&58,42,34&42\\03&58,42,23& 42\\04&37,34,23 & 34\\05&58,37,34 & 37\\06&58,37,23 & 37\\07&58,34,23 &34\\08&42,37,34 &37\\09&42,37,23 &37\\10&42,34,23 &34\end[/tex]

  2. All possible are:

    (G,L,S)

    (G,L,R)

    (G,L,P)

    (G,S,R)

    (G,S,P)

    (G,R,P)

    (L,S,R)

    (L,S,P)

    (S,R,P)

    {L,R,P)

    Probability of 1st/2nd/10th sample = 1/10

    Step-by-step explanation:

    All the possible combinations of the 3 size samples from a 5 size population have been listed without repetition.

    Total Numbers of Samples = 10

    To find the probability of finding the first sample from random sampling procedure,

    Probability = Number of desired outcomes/ Total number of outcomes

    Where Number of desired outcome is 1 and total number of outcomes is 10.

    Probability = 1/10

    Similarly, to find 2nd sample or 10th sample, the number of desired outcomes is same i.e 1, hecne the probability remains the same i.e 1/10

  3. she would want to sell 10 full-year subscriptions and at least 9 half-year subscriptions to get a total of at least $300. 

    i hope this answer you! if you have any further questions or concerns, feel free to ask! : )

    step-by-step explanation:

    mark brainliest!

    [tex]Kelly sells magazine subscriptions after work. the half-year subscriptions cost $12, and the full-ye[/tex]

  4. There are 9 possible samples for selection of two with replacement. 

    They are: (56, 56) (56, 46) (56, 60) (46, 46) (46, 56) (46, 60) (60, 60) (60, 46) (60, 56)

    Remember that when making solution sets with replacement you have the possibility of choosing the same number (or data point) twice. So in this case, you will have the number of possible answers squared for total possible answers. 

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