A cylindrical specimen of Aluminium having a diameter of 12.8 mm and gauge length of 50.8 is pulled

A cylindrical specimen of Aluminium having a diameter of 12.8 mm and gauge length of 50.8 is pulled in tension. Use the data given below to:A) Plot the data as engineering stress versus engineering strain. B) Compute the modulus of elasticity. C) Determine the yield strength at a strain offset of 0.002. D) Determine the tensile strength of this alloy. E) What is the approximate ductility, in percent elongation?Load (N) Length0 50.8007330 50.85115100 50.90223100 50.95230400 51.00334400 51.05438400 51.30841300 51.81644800 52.83246200 53.84847300 54.86447500 55.88046100 56.89644800 57.65842600 58.42036400 59.182

Related Posts

This Post Has 3 Comments

  1. a. Identify the cost hierarchy level for each cost category.

    Direct materials purses  ⇒ Output unit-level cost

    Direct materials backpacks ⇒  Output unit-level cost

    Direct manufacturing labor purses ⇒  Output unit-level cost

    Direct manufacturing labor backpacks  ⇒ Output unit-level cost

    Setup ⇒  Batch-level cost

    Shipping  ⇒ Batch-level cost

    Design  ⇒ Product-sustaining cost

    Plant utilities and administration ⇒ Facility-sustaining cost

    b.

    Setup $64,000  ⇒ number of batches (it's a batch level cost)

    Shipping $73,000   ⇒ number of batches (it's a batch level cost)

    Design $169,000   ⇒ number of designs (it's logical, design costs must be allocated based on the number of designs)

    Plant utilities and administration $221,000  ⇒ hour of production (it involves the whole manufacturing process)

    c.

    Setup $64,000  / 200 batches = $320 per batch

    Shipping $73,000  / 200 batches = $365 per batch

    Design $169,000   / 4 designs = $42,250 per design

    Plant utilities and administration $221,000  / 4,250 production hours = $52 per production hour

                                backpacks              purses                    total

    Setup                    $38,400                $25,600               $64,000

    Shipping               $43,800                $29,200               $73,000

    Design                  $84,500                $84,500             $169,000  

    Plant U&A            $86,580                 $134,420            $221,000

    totals                  $253,280                $273,720           $527,000

    d.

    total production costs for backpacks = $454,995 + $113,000 + $253,280 = $821,275

    production costs per unit = $821,275 / 6,175 = $133 per backpack

    total production costs for purses = $319,155 + $99,000 + $273,720 = $691,875

    production costs per unit = $691,875 / 3,075 = $225 per purse

    e. in order to reduce setup and shipping costs, the company needs to produce in larger batches so the total number of batches decreases.

  2. Hello the needed data given is not properly arranged attached below is the properly arranged data

    b) 62.5 * 10^3 MPa

    c) ≈ 285 MPa

    d)  370Mpa

    e)  16%

    Explanation:

    Given Data:

    cylindrical aluminum diameter = 12.8 mm

    Gauge length = 50.8 mm

    A) plot of engineering stress vs engineering strain

    attached below

    B ) calculate Modulus of elasticity

    Modulus of elasticity = Δб / Δ ε

                                       = ( 200 - 0 ) / (0.0032 - 0 ) = 62.5 * 10^3 MPa

    C) Determine the yield strength

    at strain offset = 0.002

    hence yield strength ≈ 285 MPa

    D) Determine tensile strength of the alloy

    The tensile strength can be approximated at 370Mpa because that is where it corresponds to the maximum stress on the stress  vs strain ( complete plot )

    E) Determine approximate ductility in percent elongation

    ductility in percent elongation = plastic strain at fracture * 100

    total strain = 0.165 , plastic strain = 0.16

    therefore Ductility in percent elongation = 0.16 * 100 = 16%

    [tex]A cylindrical specimen of Aluminium having a diameter of 12.8 mm and gauge length of 50.8 is pulled[/tex]
    [tex]A cylindrical specimen of Aluminium having a diameter of 12.8 mm and gauge length of 50.8 is pulled[/tex]

  3. 166.4

    Step-by-step explanation:

    [tex]12.8 \% \: of \: 1300 \\ \\ = \frac{12.8}{100} \times 1300 \\ \\ = 12.8 \times 13 \\ \\ = 166.4[/tex]

Leave a Reply

Your email address will not be published. Required fields are marked *