A farmer has 140 bushels of apples to sell at her roadside stand. She sells an average of 7 15. bushels each day. Represent the total change in the number of bushels she has for sale after 8 7 days.

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A farmer has 140 bushels of apples to sell at her roadside stand. She sells an average of 7 15. bushels each day. Represent the total change in the number of bushels she has for sale after 8 7 days.

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510

Skill Tests

With a partner, complete the Skill Tests for the six areas of skill-related fitness and record both your scores and your partner’s scores below. Answer the reflection questions.

My Scores:

Agility – Agility Square Test:

Speed – Stay on Your Toes Test:

Reaction Time – Ready, Set, Go Test:

Balance – Stork Stance Test:

Coordination – Off the Wall Test:

Power – Standing Long Jump Test:

Partner Scores:

Agility – Agility Square Test:

Speed – Stay on Your Toes Test:

Reaction Time – Ready, Set, Go Test:

Balance – Stork Stance Test:

Coordination – Off the Wall Test:

Power – Standing Long Jump Test:

Compare your scores to your partner’s scores. Explain the reason for any differences.

How can improving your balance and coordination affect your performance in sports or recreational activities?

What activity was the most difficult for you to perform? Why?

Describe an activity that could help improve your striking and your reaction time skills.

Select a physical activity or sport that you have never done but would like to try one day. Identify at least one element of skill-related fitness that is important to being successful in this activity.

What power-increasing activities do you need to perform regularly to improve your performance?

answer: [tex]\frac{sin40^{\circ}}{x} = \frac{sin60^{\circ}}{12}[/tex]

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

[tex]\frac{sin40^{\circ}}{x} = \frac{sin60^{\circ}}{12}[/tex]

which is the required equation for finding the value of x,

[tex]\frac{x}{sin40^{\circ}}= \frac{12}{sin60^{\circ}}[/tex]

[tex]x= 12\times \frac{sin40^{\circ}}{sin60^{\circ}}[/tex]

[tex]x= 12\times 0.74222719896[/tex]

[tex]x= 8.90672638762\approx 8.967[/tex]