A ferris wheel is 40 meters in diameter and boarded from a platform that is 1 meters above the ground. The six o'clock position on the ferris wheel is level with the loading platform. The wheel completes 1 full

revolution in 4 minutes. The function h = f(t) gives your height in meters above the ground t minutes after

the wheel begins to turn. Write an equation for h = f(t).

t = 2.9517 min

Step-by-step explanation:

Given

D = 40 m ⇒ R = D/2 = 40 m/2 = 20 m

ybottom = 2 m

ytop = ybottom + D = 40 m + 2 m = 42 m

yref = 34 m

t = 10 min

The height above the ground (y) is a sinusoidal function.

The minimum height is ybottom = 2 m

The maximum height is ytop = 42 m;

The midline is (ybottom + ytop)/2 = (2 m + 42 m)/2 = 22 m

If we model the wheel as follows

x² + y² = R²

where

y = yref - (R + ybottom) = 34 m - (20 m + 2 m) = 12 m

R = 20 m

we have

x² + (12 m)² = (20)²

⇒ x = 16 m

then

tan (θ/2) = x/y

⇒ tan (θ/2) = 16 m/12 m

⇒ θ = 106.26°

Knowing the angle of the circular sector, we apply the relation

t = (106.26°)*(10 min/360°)

⇒ t = 2.9517 min

Since the period of revolution is 10 minutes, the ride is above 34 meters for 2.9517 minutes each revolution.

40 i don’t know lololol

[tex]** asap (20 points)what is the total surface area of the square pyramid[/tex]

d is ur answer hopes this i dont really know how to explain it to u.

t >.696 minute

Step-by-step explanation:

Given, r = 40 m

[tex]p=2\pi r[/tex]

[tex]p=80\pi[/tex]

Given, t = 5 min for one revolution

[tex]v=p/t[/tex]

[tex]80\pi /5= 16\pi[/tex]

time to reach to more than 35 m

[tex]35< 16\pi t[/tex]

[tex]t 35/16\pi[/tex]

[tex]t .696 min[/tex]