A scientist makes an acid solution by adding drops of acid to 1.2 L of water. The final volume of the acid solution is 1.202 L. Assuming

A scientist makes an acid solution by adding drops of acid to 1.2 L of water. The final volume of the acid solution is 1.202 L. Assuming the volume of each drop is 0.05 mL, how many drops were added to the water? About what percent of the acid solution is acid?

9. Find the area of a circle having a circumference of 382. Round to the nearest tenth. Use 3.14 for 1. a. 1133.5 units b. 1078.6

1. ltuthill says:

Step-by-step explanation:

volume of acid = 1.202-1.2 = 0.002 l = 0.002×1000 = 2ml

Volume of each drop = 0.05ml

Number of drops =

2. JulietteRosso995 says:

- 40 drops and the percentage of acid in acid solution is 0.166%.

Solution:- Acid is added drops wise to 1.2 L of water to make acid solution. The final volume of the acid solution is 1.202 L. From here we could calculate the volume of the acid added to water by subtracting water volume from final acid solution volume as:

volume of acid added = 1.202 L - 1.2 L = 0.002 L

It's given that the volume of each drop is 0.05 mL. let's convert the volume of acid added from L to mL.

= 2mL

Now let's calculate the number of drops of acid added to water as:

= 40 drops

0.002 L of acid are present in 1.202 L of solution. It asks to calculate about what percent of acid solution is acid means how many L of acid are present in 100 L of acid solution. It's done as:

percentage of acid in acid solution =

= 0.166%

So, 40 drops of acid are required and there is 0.166% of acid in acid solution.

Step-by-step explanation:

volume of acid = 1.202-1.2 = 0.002 l = 0.002×1000 = 2ml

Volume of each drop = 0.05ml

Number of drops =

4. dbegay36 says:

- 40 drops and the percentage of acid in acid solution is 0.166%.

Solution:- Acid is added drops wise to 1.2 L of water to make acid solution. The final volume of the acid solution is 1.202 L. From here we could calculate the volume of the acid added to water by subtracting water volume from final acid solution volume as:

volume of acid added = 1.202 L - 1.2 L = 0.002 L

It's given that the volume of each drop is 0.05 mL. let's convert the volume of acid added from L to mL.

$0.002L(\frac{1000mL}{1L})$

= 2mL

Now let's calculate the number of drops of acid added to water as:

$2mL(\frac{1drop}{0.05mL})$

= 40 drops

0.002 L of acid are present in 1.202 L of solution. It asks to calculate about what percent of acid solution is acid means how many L of acid are present in 100 L of acid solution. It's done as:

percentage of acid in acid solution = $(\frac{0.002}{1.202})100$

= 0.166%

So, 40 drops of acid are required and there is 0.166% of acid in acid solution.