A square has a perimeter of 12 units. One vertex is at the point (-1,1), and another vertex is at the vertex (2,4) which of the

A square has a perimeter of 12 units. One vertex is at the point (-1,1), and another vertex is at the vertex (2,4) which of the following could be another vertex? (1,2)
(2,1)
(1,-2)
(2,-1)​

This Post Has 4 Comments

1. Expert says:

If i could just have the statements, i'd be able to

2. Expert says:

5/20 so 25%

step-by-step explanation:

$Plz i only need the last question answerd$

3. Expert says:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

$m_ {1} * m_ {2} = - 1$

then, given the following line:

$6x-3y = 18\\6x-18 = 3y$

$\frac {6x} {3} - \frac {18} {3} = y\\y = \frac {6x} {3} - \frac {18} {3}\\y = 2x-6$

so, $m_ {1} = 2$

we are looking for m_ {2}:

$m_{2}=\frac{-1}{m_{1}}\\m_{2}=\frac{-1}{2}\\m_{2}=-\frac{1}{2}$

then, the line is given by:

$y = - \frac {1} {2} x + b$

we find "b" replacing the given point:

$8 = - \frac {1} {2} (0) + b\\8 = b$

finally, the equation is:

$y = - \frac {1} {2} x + 8$

option c

$Me it is a geometry question and you$

4. Expert says:

98%

step-by-step explanation: