A square has a perimeter of 12 units. One vertex is at the point (-1,1), and another vertex is at the vertex (2,4) which of the following could be another vertex? (1,2)

(2,1)

(1,-2)

(2,-1)

Skip to content# A square has a perimeter of 12 units. One vertex is at the point (-1,1), and another vertex is at the vertex (2,4) which of the

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A square has a perimeter of 12 units. One vertex is at the point (-1,1), and another vertex is at the vertex (2,4) which of the following could be another vertex? (1,2)

(2,1)

(1,-2)

(2,-1)

If i could just have the statements, i'd be able to

5/20 so 25%

step-by-step explanation:

[tex]Plz i only need the last question answerd[/tex]

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

[tex]m_ {1} * m_ {2} = - 1[/tex]

then, given the following line:

[tex]6x-3y = 18\\6x-18 = 3y[/tex]

[tex]\frac {6x} {3} - \frac {18} {3} = y\\y = \frac {6x} {3} - \frac {18} {3}\\y = 2x-6[/tex]

so, [tex]m_ {1} = 2[/tex]

we are looking for m_ {2}:

[tex]m_{2}=\frac{-1}{m_{1}}\\m_{2}=\frac{-1}{2}\\m_{2}=-\frac{1}{2}[/tex]

then, the line is given by:

[tex]y = - \frac {1} {2} x + b[/tex]

we find "b" replacing the given point:

[tex]8 = - \frac {1} {2} (0) + b\\8 = b[/tex]

finally, the equation is:

[tex]y = - \frac {1} {2} x + 8[/tex]

option c

[tex]Me it is a geometry question and you[/tex]

98%

step-by-step explanation: