A square has a perimeter of 12 units. One vertex is at the point (-1,1), and another vertex is at the vertex (2,4) which of the following could be another vertex? (1,2)
(2,1)
(1,-2)
(2,-1)
A square has a perimeter of 12 units. One vertex is at the point (-1,1), and another vertex is at the vertex (2,4) which of the following could be another vertex? (1,2)
(2,1)
(1,-2)
(2,-1)
If i could just have the statements, i'd be able to
5/20 so 25%
step-by-step explanation:
[tex]Plz i only need the last question answerd[/tex]
for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.
[tex]m_ {1} * m_ {2} = - 1[/tex]
then, given the following line:
[tex]6x-3y = 18\\6x-18 = 3y[/tex]
[tex]\frac {6x} {3} - \frac {18} {3} = y\\y = \frac {6x} {3} - \frac {18} {3}\\y = 2x-6[/tex]
so, [tex]m_ {1} = 2[/tex]
we are looking for m_ {2}:
[tex]m_{2}=\frac{-1}{m_{1}}\\m_{2}=\frac{-1}{2}\\m_{2}=-\frac{1}{2}[/tex]
then, the line is given by:
[tex]y = - \frac {1} {2} x + b[/tex]
we find "b" replacing the given point:
[tex]8 = - \frac {1} {2} (0) + b\\8 = b[/tex]
finally, the equation is:
[tex]y = - \frac {1} {2} x + 8[/tex]
option c
[tex]Me it is a geometry question and you[/tex]
98%
step-by-step explanation: