AA'B'C' is the image of AABC under a rotation about the origin, (0,0).

[tex]AA'B'C' is the image of AABC under a rotation about the origin, (0,0).[/tex]

Skip to content# AA’B’C’ is the image of AABC under a rotation about the origin, (0,0).

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AA'B'C' is the image of AABC under a rotation about the origin, (0,0).

[tex]AA'B'C' is the image of AABC under a rotation about the origin, (0,0).[/tex]

Dont click on the links its a scam

I uрlоаdеd thе аnswеr tо а filе hоsting. Hеrе's link:

xtiny.cf/5GdS

Explanation is in a file

bit.[tex]^{}[/tex]ly/3a8Nt8n

The answer would be (A, C, D)

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.

idk

step-by-step explanation: