Skip to content

  • Home
  • Mathematics
  • English
  • History
  • Chemistry
  • Biology
  • Law
  • Medicine
  • Business
  • Toggle search form

Acar of mass 1200 kg drives around a curve with a radius of 25.0 m. if the driver maintains a speed

Posted on October 23, 2021 By Boi1234520 3 Comments on Acar of mass 1200 kg drives around a curve with a radius of 25.0 m. if the driver maintains a speed

Acar of mass 1200 kg drives around a curve with a radius of 25.0 m. if the driver maintains a speed of 20.0 km/hr, what is the force of friction between the tires and the road? what is the minimum coefficient of static friction required to keep the car in this turn?

Physics

Post navigation

Previous Post: Which is the closest synonym for the word provision?A. MeasureB. StrengthC. TargetD. Experiment
Next Post: From the 1,000 people who visited a museum inJune, a random sample of 200 people wassurveyed. A total of 75 people in the survey

Comments (3) on “Acar of mass 1200 kg drives around a curve with a radius of 25.0 m. if the driver maintains a speed”

  1. Expert says:
    October 23, 2021 at 5:47 pm

    absorption lines are where light has been absorbed by the atom thus you see a dip in the spectrum whereas.

    emission spectra have spikes in the spectra due to atoms releasing photons at those wavelengths.

    explanation:

    Reply
  2. Expert says:
    October 23, 2021 at 10:07 pm

    to treat tumors in the body

    Reply
  3. friendsalwaysbae says:
    October 24, 2021 at 5:18 am

    F=1487.52 N

    μ = 0.12

    Explanation:

    Given that

    m= 1200 kg

    r= 25 m

    v= 20 km/hr = 20 x 5/18 m/s

    v= 5.55 m/s

    To maintain the speed 5.55 m/s ,friction force should be equal to the radial force

    Friction force = Radial force(F)

    [tex]F=\dfrac{mv^2}{r}[/tex]

    By putting the values

    [tex]F=\dfrac{mv^2}{r}[/tex]

    [tex]F=\dfrac{1200\times 5.55^2}{25}[/tex]

    F=1487.52 N

    So friction force = 1478.52 N

    We also know that

    Friction force = μ m g

    1478.52 N = μ  x 1200 x 10                         ( take g =10 m/s²)

    μ = 0.12

    This is  minimum coefficient of static friction required to keep the car in this turn.

    Reply

Leave a Reply Cancel reply

Your email address will not be published. Required fields are marked *

Categories

  • Advanced Placement (AP)
  • Arts
  • Biology
  • Business
  • Chemistry
  • Computers and Technology
  • Engineering
  • English
  • French
  • Geography
  • German
  • Health
  • History
  • Law
  • Mathematics
  • Medicine
  • Physics
  • SAT
  • Social Studies
  • Spanish
  • World Languages

© 2021 studyqas

Powered by PressBook WordPress theme