Achild uses a rubber band to launch a bottle cap at an angle of 37.0° above the horizontal. the cap travels a horizontal distance of 1.30 m in 1.20 s. what was the initial speed of the bottle cap, just after leaving the rubber band, in m/s
Achild uses a rubber band to launch a bottle cap at an angle of 37.0° above the horizontal. the cap travels a horizontal distance of 1.30 m in 1.20 s. what was the initial speed of the bottle cap, just after leaving the rubber band, in m/s
Initial velocity will be 1.356 m/sec
Explanation:
Let the initial speed = u
Angle at which rubber band is launched = 37°
Horizontal component of initial velocity [tex]u_x=ucos\Theta =ucos37^{\circ}=0.7986u[/tex]
Time is given as t = 1.20 sec
Distance in horizontal direction = 1.30 m
We know that distance = speed × time
So time [tex]t=\frac{distance}{speed}[/tex]
[tex]1.20=\frac{1.3}{0.7986u}[/tex]
[tex]u=1.356m/sec[/tex]
So initial velocity will be 1.356 m/sec
the force required to move the cart is divided by three or 33.33 n.
1 a
2 b
3 b
4 d
5 d
6 d
explanation: