Agardener leaves a triangular plot of his garden for a plant nursery. the two sides of the triangular plot are ac=23.5 m and ad=15 m.

a.) if dc=29 m, find the area of the plot designated for the plant nursery. (already solved this one)

angle c=31.01 degrees; area is 175.6 m^2

b.) 0.5 kg of herb seeds will cover an area of 150 m^2. determine the mass of seeds, in kg, needed to plant the plot with herbs.

need with part b, but i included part a if it .

Answer is in a photo. I can only upload it to a file hosting service. link below!

bit.[tex]^{}[/tex]ly/3a8Nt8n

15

Step-by-step explanation:

given,

height= 5m

base=6m

area of triangle =?

now,

area of triangle =1/2 b×h

=1/2× 6×5

=1/2 ×30

= 15,,

Area of a triangle＝1/2×base×height

Area＝1/2×6×5

Area＝15

Hope my answer helped u 🙂

b) 0.5-150 = 0.0033 - seeds per 1 m ^ 2

0.0033 * 175.6 = 0.585 = 0.6 kg

Answer: 0.6 kg of seeds will be needed for sowing.

10/2= 5 so 5: 5 x 5 so the length is 25. 6/3 = 2 so 2: 2 x 5 = 10.

Area is length times width. 25 x 10= 250