# Agardener leaves a triangular plot of his garden for a plant nursery. the two sides of the triangular

Agardener leaves a triangular plot of his garden for a plant nursery. the two sides of the triangular plot are ac=23.5 m and ad=15 m.
a.) if dc=29 m, find the area of the plot designated for the plant nursery. (already solved this one)
angle c=31.01 degrees; area is 175.6 m^2
b.) 0.5 kg of herb seeds will cover an area of 150 m^2. determine the mass of seeds, in kg, needed to plant the plot with herbs.
need with part b, but i included part a if it .

## This Post Has 5 Comments

1. crtlq says:

A⁣⁣⁣⁣⁣nswer i⁣⁣⁣⁣s i⁣⁣⁣⁣n a p⁣⁣⁣⁣hoto. I c⁣⁣⁣⁣an o⁣⁣⁣⁣nly u⁣⁣⁣⁣pload i⁣⁣⁣⁣t t⁣⁣⁣⁣o a f⁣⁣⁣⁣ile h⁣⁣⁣⁣osting s⁣⁣⁣⁣ervice. l⁣⁣⁣⁣ink b⁣⁣⁣⁣elow!

bit.$^{}$ly/3a8Nt8n

2. MGA20078 says:

15

Step-by-step explanation:

given,

height= 5m

base=6m

area of triangle =?

now,

area of triangle =1/2 b×h

=1/2× 6×5

=1/2 ×30

= 15,,

3. deonharris18 says:

Area of a triangle＝1/2×base×height
Area＝1/2×6×5
Area＝15

Hope my answer helped u 🙂

4. firenation18 says:

b) 0.5-150 = 0.0033 - seeds per 1 m ^ 2
0.0033 * 175.6 = 0.585 = 0.6 kg

Answer: 0.6 kg of seeds will be needed for sowing.

5. DenniJ19 says:

10/2= 5 so 5: 5 x 5 so the length is 25. 6/3 = 2  so 2: 2 x 5 = 10.
Area is length times width. 25 x 10= 250