# Agas that exerts a pressure of 845 mm hg in a container with a volume of 4.60 l will

Agas that exerts a pressure of 845 mm hg in a container with a volume of 4.60 l will exert a pressure of 368 mm hg when transferred to a container with a volume of l

## This Post Has 3 Comments

1. Expert says:

remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.

2. my1445 says:

- 10.6 L.

Solution:- Temperature is not given in this problem so it must be constant and we know that at constant temperature, the volume of the gas is inversely proportional to it's pressure. It is Boyle's law.

The equation for this law is written as:

$P_1V_1=P_2V_2$

P stands for pressure and V stands for volume and the subscripts 1 and 2 are representing initial and final values.

Initial pressure is 845 mmHg, initial volume is 4.60 L. Final volume is 368 mmHg and it asks to calculate the final volume.

Let's plug in the values in the equation and solve it for final volume.

$845mmHg(4.60L)=368mmHg(V_2)$

divide both sides by 368mmHg:

$V_2=\frac{845mmHg(4.60L)}{368mmHg}$

$V_2$  = 10.6 L

So, the gas is transferred to a container with a volume of 10.6 L.

3. Expert says:

answer: any goods being imported from another country may be subject to issued by the federal government are tariffs

explanation:

tariffs are a tax on anything that are imported from abroad. government use them to protect and boost their local industries and the thought is that they encourage consumers to buy local instead of importing and they will hope will protect jobs and economy in the country that implements them