# Amaya’s test scores in algebra 1 are 48 and 61. she has one more test left and wants to earn a d for

Amaya's test scores in algebra 1 are 48 and 61. she has one more test left and wants to earn a d for the course, which is from 60-69 inclusive. write a compound inequality to repesent the situation and solve the inequality to find the range of scores amaya has to earn to get a d in algebra 1. amaya must get greater than or equal to a

## This Post Has 2 Comments

1. cmir says:

Amaya's overall grade will be an average of all the scores. To find the average, we must add up the scores and divide by the number of tests.

We know 2 of the scores, so we can represent the average as:

(48+61+x)/3

Now write the inequality.

60 <= (109 + x)/3 <= 69

Now let's find the lower bound to receive a D. First we need to multiply both sides by 3.

180 <= 109+x

Now subtract 109.

71 <= x

Now let's find the upper bound. Do the same thing but with the 69.

109+x <= 207

x <= 98

So Amaya will receive an overall grade of a D if she scores anywhere from 71 to 98 on the test.

2. reneebrown017 says:

The first thing you should do before writing the compound inequation is to know what Amaya's grade point average is.
The average grade for the three exams is:
(48 + 61 + x) / 3
Then, she wants to get a D in the course, then we have two inequations:
(48+61+x)/3 >=60
(48 + 61 + x) / 3 <= 69
The compound inequation is:
60 <= (48 + 61 + x) / 3 <= 69
Solving the compound inequation:
(48 + 61 + x) / 3> = 60
(48 + 61 + x) / 3 = 60
(48 + 61 + x) = 180
x = 180 - 48 - 61 = 71
On the other hand,
(48 + 61 + x) / 3 <= 69
(48 + 61 + x) / 3 = 69
x = 207 - 48 - 61 = 98