# Amovie theater sells adult tickets for $13 and student tickets for$8 . tuesday, a total of 56 tickets

Amovie theater sells adult tickets for $13 and student tickets for$8 . tuesday, a total of 56 tickets were sold, and the total money collected was $568 . how many adult tickets and how many student tickets were sold? ### Related Posts ## Which of the following are parallel to the line 2x+ 4y=16 ## 7.(06.02)Nami plotted the graph below to show the relationship between the temperature of her city ## 3. Lolly and Molly are reading a book. Lolly is on page 30 and reads 4 pages a minute.Molly is on page 40 and reads two pages ## On a scale drawling with the scale of 1 in to 5ft to aflagpole is 4 inches tall how tall is the actual flagpole ## Renting a trailer for 4 days costs$84. Renting the trailer for 5 days costs $100. Which of the following ## 9. Find the area of a circle having a circumference of 382. Round to the nearest tenth. Use 3.14 for 1. a. 1133.5 units b. 1078.6 ## This Post Has 4 Comments 1. josephnievesr31 says: Let a ault tickets and s student tickets be sold. a+s=56 13a+8s=568 s=56-a 13a+8(56-a)=568 13a+448-8a=568 5a+448=568 5a=120 a=24 s=56-24=32 24 adult tickets and 32 student tickets are sold. 2. Expert says: Ican’t sorry i would if i could 3. elijahjacksonrp6z2o7 says: Your solving a linear equation for this problem the easiest method of the 3 is going to be solving by elimination: 1. The adult tickets (A) coast$13 per adult and student tickets (S) coast $8. The theater sold$568 worth of tickets. because we don't know how many of each tickets were sold we multiply the prices of adults by one variable and the price of students by another variable to add up to a total of \$586 hence the equation 13a+8s=568

For the second equation you simply want to add the number of adult tickets and the number of student tickets together to get the total amount of tickets which in this case Is 56 hence the equation a+s=56
13A+8S=568
A+S=56

2. the next step would be to add the equation to solve for either A or Sby first seeing if any of the variables cancel each other out. In this case they don't so you need to multiply one of the equations to make it so one of the variables cancel out. I multiplied the second equation by -13 (I chose the second equation because it's easiest) so you and up with -13(a+b=56) and then using distributive property you and up with the equation -13a-13s=-728 so your new equation ends up as:
13A+8S=568
-13A-13s=-728

3. now you can add the equations together 13a+-13a=0 (cancel each other out) 8s+-13s=-5s and 568+-728=-160 so you and up with -5s=-160

13a+8s=568
+-13a-13s=-728
-5s=-160

4. now you want to isolate s by dividing -5 into -160 which is 32 hence s=32

s=-160÷-5=32
s=32

5. now that you have your value for s you can plug it in to either equation (I used the second because it's easiest) and then to find the value of a you have to isolate a so you subtract 32 from both sides so you get a=56-32 therefore a= 24
a+32=56
a=56-32
a=24

6.You now have both values of your variables
the theater sold 32 student tickets and 24 adult tickets

4. Expert says:

the answer is 15% decrease