An opaque bag contains 5 green marbles, 3 blue marbles, and 2 red marbles. if a marble is drawn at random what are the odds of drawing a red marble?

1: 2

1: 4

1: 5

4: 5

[tex]An opaque bag contains 5 green marbles, 3 blue marbles, and 2 red marbles. if a marble is drawn at r[/tex]

2 : 5 + 3 + 2

2 : 10

Simplifies to 1 : 5

An opaque bag contains 5 green marbles, 3 blue marbles, and 2 red marbles. If a marble is drawn at random what are the ODDS of drawing a red marble?

1:4

What is the probability of flipping a penny and a nickel and having them both land on heads?

25%

*100% CORRECT ANSWERS

Question 1

What is the approximate Probability of drawing a RED FACE card from a standard deck of shuffled cards.

11.5%

Question 2

An opaque bag contains 5 green marbles, 3 blue marbles, and 2 red marbles. If a marble is drawn at random what are the ODDS of drawing a red marble?

1:4

Question 3

What is the probability of flipping a penny and a nickel and having them both land on heads?

25%

Question 4

A solider is parachute training. He jumps out of a plane high enough that the pilot determines the solider will land somewhere in an 240 foot radius land zone. The pilow forgot to mention to the solider that the parachute has very little maneuverablity (no steering). and there are 30 trees in the landing zone. Each tree from the air practically outlines a circle with a radius of 8 feet. What is the geometric probability that the solider will land in a tree?

0.03333

Question 5

A repair person is scheduled to be at your apartment between 9:00am to 12:00pm but you have to leave at 11:30 to help out a friend. If the repair person is equally likely to be at your apartment any time during the appointment time, what is the probability that you will be there?

83.3%

[tex]\dfrac{1}{3}[/tex]

Step-by-step explanation:

Given : An opaque bag contains 5 green marbles, 3 blue marbles and 2 red marbles.

Total marbles = 5+3+2=10

Now, if it given that the a red marble is already drawn, then the total marbles left in the bag = 10-1=9

But the number of blue marbles remains the same.

Now, the probability of drawing a blue marble given the first marble was red :-

[tex]=\dfrac{\text{Number of blue marbles}}{\text{Total marbles left}}\\\\=\dfrac{3}{9}=\dfrac{1}{3}[/tex]

Hence, the required probability = [tex]\dfrac{1}{3}[/tex]

Odds are 3 to 7

Step-by-step explanation:

The odds are defined as the probability that the event will occur divided by the probability that the event will not occur.

Let's find:

Probability of blue marble = 3/10 [ 3 blue and 10 in total]

Probabilty of NOT blue marble = 7/10 [7 marbles are red and green (not blue) and 10 in total]

Hence,

Odds of drawing a blue marble = [tex]\frac{\frac{3}{10}}{\frac{7}{10}}=\frac{3}{10}*\frac{10}{7}=\frac{3}{7}[/tex]

The odds are 3 to 7

An opaque bag contains 5 green marbles, 3 blue marbles, and 2 red marbles. If a marble is drawn at random what are the ODDS of drawing a red marble?

1:4

*100% CORRECT ANSWERS

Question 1

What is the approximate Probability of drawing a RED FACE card from a standard deck of shuffled cards.

11.5%

Question 2

1:4

Question 3

What is the probability of flipping a penny and a nickel and having them both land on heads?

25%

Question 4

A solider is parachute training. He jumps out of a plane high enough that the pilot determines the solider will land somewhere in an 240 foot radius land zone. The pilow forgot to mention to the solider that the parachute has very little maneuverablity (no steering). and there are 30 trees in the landing zone. Each tree from the air practically outlines a circle with a radius of 8 feet. What is the geometric probability that the solider will land in a tree?

0.03333

Question 5

A repair person is scheduled to be at your apartment between 9:00am to 12:00pm but you have to leave at 11:30 to help out a friend. If the repair person is equally likely to be at your apartment any time during the appointment time, what is the probability that you will be there?

83.3%

Step-by-step explanation:

The First Question !

This is simple,

So first we set this problem up

2 Red + 3 Blue + 7 Green = 12 Total Marbles

The formula for calculator probability is

# of favorable outcomes / # of possible outcomes

The number of favorable outcomes we have is 3 because we are trying to find the probability of pulling out a blue marble

The number of possible outcomes is 12 because we have 12 total marbles

3/12 simplifies to 1/4 which is .25

The probability of drawing a blue marble is 0.25 or 25%

Second Question!

The probability of getting heads on the toss of a coin is 0.5. If we consider all possible outcomes of the toss of two coins as shown, there is only one outcome of the four in which both coins have come up heads, so the probability of getting heads on both coins is 0.25. The second useful rule is the Sum Rule.

I Hope It's Helpful :0

[tex]\dfrac{1}{3}[/tex]

Step-by-step explanation:

Given : An opaque bag contains 5 green marbles, 3 blue marbles and 2 red marbles.

Total marbles = 5+3+2=10

Now, if it given that the a red marble is already drawn, then the total marbles left in the bag = 10-1=9

But the number of blue marbles remains the same.

Now, the probability of drawing a blue marble given the first marble was red :-

[tex]=\dfrac{\text{Number of blue marbles}}{\text{Total marbles left}}\\\\=\dfrac{3}{9}=\dfrac{1}{3}[/tex]

Hence, the required probability = [tex]\dfrac{1}{3}[/tex]

1/9 is the probability

If you add all of the marbles(10) and then chose the red(2) and make it a fraction 2/10, then reduce it by dividing the numerator and denominator by the same number (2) the the answer is C) 1:5

Option C is the correct answer.

Step-by-step explanation:

Given that an opaque bag contains 5 green marbles, 3 blue marbles, and 2 red marbles.

Total number of marbles = 5+3+2 = 10

We need to find the ODDS of drawing a red marble.

Total number of red marble = 2

Chance for getting a red marble is the ratio of number of red marbles to total number of marbles.

[tex]\texttt{Chance for getting a red marble=}\frac{2}{10}=\frac{1}{5}[/tex]

ODDS of drawing a red marble = 1 : 5

Option C is the correct answer.