Another geometry question

- geometry

[tex]Another geometry question - geometry[/tex]

Skip to content# Another geometry question – geometry

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Another geometry question

- geometry

[tex]Another geometry question - geometry[/tex]

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2

Step-by-step explanation:

The 2 point are (9, -1) & (4, -11)

To fnd the slope you need to use the equation y2-y1/x2-x1

When you substitute that in it is -11+1/4-9

When you fully simplify that it should be 2

The slope is 2

y2-y1/x2-x1

(9,-1) (4-11)

-1+11/9-4

10/5

2

answer:It was -40 this morning so the kids boiled some water and threw it outside. Super cool effect. We wondered, "what would happen if we did this with coloured water." We put red food colouring (gel) in it and it dissolved. When it was thrown, it almost immediately separated from the water and fell downward while the plume of evaporation went up. (I wish I could attach the photos for you to see). Why would this be? Would the food colouring have a higher boiling point? Can you help me understand what happened here. Also, would the implications be that the water cycle has been cleaning the water for years, but with new chemicals with lower boiling points be entering our water system and unable to be removed?

answer:

It is very hard to give a definitive answer because your description is pretty vague. My best guess would be that something in the food color made it remain liquid when the water froze so that it separated. For example, propylene glycol, which is used in many food colorings, has a melting point around -60°C so it would not freeze at -40°

Step-by-step explanation:

Part 1) m∠1 =(1/2)[arc SP+arc QR]

Part 2) [tex]PR^{2} =PS*PT[/tex]

Part 3) PQ=PR

Part 4) m∠QPT=(1/2)[arc QT-arc QS]

Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

m∠1 -----> is the inner angle

The arcs that comprise it and its opposite are arc SP and arc QR

so

m∠1 =(1/2)[arc SP+arc QR]

Part 2)

we know that

The Intersecting Secant-Tangent Theorem, states that the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.

so

In this problem we have that

[tex]PR^{2} =PS*PT[/tex]

Part 3)

we know that

The Tangent-Tangent Theorem states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

so

In this problem

PQ=PR

Part 4)

we know that

The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

m∠QPT -----> is the outer angle

The arcs that it encompasses are arc QT and arc QS

therefore

m∠QPT=(1/2)[arc QT-arc QS]