# Answer. a^2+4a+16 a^2+15a+75 a^2+14a+49 a^2+26a+169 which expressions are differences of squares? select each correct answer.

a^2+4a+16

a^2+15a+75

a^2+14a+49

a^2+26a+169

which expressions are differences of squares?

a^2−36

x^2+25

w^2−121

n^2−50

## This Post Has 10 Comments

1. silas99 says:

Whaaa how old are you this is hard boy

2. salmanderabdi12 says:

A²-b² is difference

A. t²-1², yep
B. nope, not difference
C. n²-15²,yep
D. we can force it but I wouldn''t pick this one

A and C

3. mutesheep says:

Step-by-step explanation:

$Which expressions are differences of squares? select each correct answer. h2−20 t2−4 x2−169 a2+1$

4. brainy51 says:

The correct options are 3 and 4.

Step-by-step explanation:

The difference of squares is defined as

$a^2-b^2$

In option 1,

$k^2+81$

It can be written as

$k^2+9^2$

It is the sum of squares, therefore the option 1 is incorrect.

In option 2,

$P^2-40$

The number 40 is not a complete square of any number, therefore option 2 is incorrect.

In option 3,

$n^2-225$

It can be rewritten as

$n^2-(15)^2$

It is the difference of squares, therefore option 3 is correct.

In option 4,

$t^2-1$

It can be rewritten as

$t^2-1^2$

It is the difference of squares, therefore option 4 is correct.

5. ashleymartinez147 says:

Step-by-step explanation:

$Which expressions are differences of squares? select each correct answer. h2−20 t2−4 x2−169 a2+1$

6. Tooey6225 says:

1. the perfect squares in this case are
a²+26a+169 = (a+13)²
a²+14a+49 = (a+7)²

2. factorising
4p²+36p+81
product = 324
sum = 36
numbers are 18 and 18
Thus , 4p²+18p+18p+81
2p(2p+9) +9p(2p+9)
thus, (2p+9p)(2p+9p)

3. Factor 81a36-64b16
this is the difference between two squares, such that;
a²-b² = (a+b)(a-b)
therefore, 81a36 -64b16 will be;
(9a18-8b8)(9a18+8b8)

4.  The differences between two squares is such that;
a²-b² = (a+b)(a-b)
therefore in this case, the difference between two squares will be;
x²-169 = (a-13)(a+13), and
t²-4     = (t-4)(t+4)

7. emilygoolsby2123 says:

A and B
Because t^2-(1)^2
(n)^2-(15)^2

8. conroyjoann22 says:

Option B, C and D are correct.

$a^2-36$, $w^2-121$ and $n^2-50$

Step-by-step explanation:

For any real number a and b:

Difference of square is given by:

$a^2-b^2 = (a-b)(a+b)$

We have to find Which expressions are differences of squares.

Option A :

$x^2+25$

⇒$x^2+5^2$

This cannot be written as a difference of square.

Option B:

$a^2-36$

⇒$a^2-6^2$

⇒$(a-6)(a+6)$

Option C:

$w^2-121$

⇒$w^2-11^2$

⇒$(w-11)(w+11)$

Option D:

$n^2-50$

⇒$n^2-(\sqrt{50})^2$

⇒$(n-\sqrt{50})(n+\sqrt{50})$

Therefore, the expressions which are are differences of squares are:

$a^2-36$, $w^2-121$ and $n^2-50$

9. meramera50 says:

Step-by-step explanation:

1. the perfect squares in this case are

a²+26a+169 = (a+13)²

a²+14a+49 = (a+7)²

First and fourth option are correct.

2. factorise  4p²+36p+81

Product = 324 and sum = 36

numbers are 18 and 18

∴  4p²+18p+18p+81

⇒ 2p(2p+9) +9(2p+9)

⇒ (2p+9)(2p+9) ⇒ $(2p+9)^2$

3. Factor $81a^36-64b^16$

As $a^2-b^2=(a+b)(a-b)$

∴  $81a^36-64b^16=(9a^18)^2-(8b^8)^2$

=$(9a^18-8b^8)(9a^18+8b^8)$  (Option B)

4.  The differences between two squares is such that;

a²-b² = (a+b)(a-b)

$x^2-169=x^2-13^2=(a-13)(a+13)$, and

$t^2-4=t^2-2^2=(t-2)(t+2)$

First and third option correct.

10. batmanmarie2004 says:

A and C are correct because they can be factorized to get (a+6)(a-6) and (w+11)(w-11) while B and D can't be factorized to get those