draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring). so find the distance between (1,2) and (4,2). that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3. it is a regular polygon which means all sides are congruent. you have 6 sides (hexa) so multiply 6 by 3 to receive 18.
x² + 3x + 7 = 0 [ax² + bx + c]
a = 1
b = 3
c = 7
quadratic formula:
[tex]x = \frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex] (+/- is this ±)
plug in the numbers into the variables
[tex]x = \frac{-3+/-\sqrt{3^2-4(1)(7)} }{2(1)}[/tex]
[tex]x=\frac{-3+/-\sqrt{9-28} }{2}[/tex]
[tex]x=\frac{-3+/-\sqrt{-19} }{2}[/tex]
your answer is a
[tex]What is the solution to this equation? x^2+3x+7=0[/tex]
b.
step-by-step explanation:
18
step-by-step explanation:
draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring). so find the distance between (1,2) and (4,2). that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3. it is a regular polygon which means all sides are congruent. you have 6 sides (hexa) so multiply 6 by 3 to receive 18.
Sorry i meant b in the other question
[tex]Looking at def, which statement below is true? i think the answer is b[/tex]