Apuppy and a kitten are 180 meters apart when they see each other. the puppy can run at a speed of 25 m/sec, while the kitten can run at a speed of 20 m/sec. a how soon will they meet if they simultaneously start running towards each other?

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Apuppy and a kitten are 180 meters apart when they see each other. the puppy can run at a speed of 25 m/sec, while the kitten can run at a speed of 20 m/sec. a how soon will they meet if they simultaneously start running towards each other?

Make two equations representing the position of each animal, p and k, for the puppy and kitten respectively.

p=25t and k=180+20t

The puppy will catch the kitten when p=k so we can say:

25t=180+20t subtract 20t from both sides

5t=180 divide both sides by 5

t=36

So the puppy will catch the kitten after 36 seconds.

It seems it should be the other way... . How soon will the puppy catch up with the kitten.

The way you have it the kitten will never catch the pup. There is already 180m between them so, the distance will only increase because the puppy runs faster than the cat.

If the puppy runs after the cat, will eventually catch up with it and can be calculated. Not the other way around.

If the pup runs after the cat, the distance between them will decrease and the pup will catch the cat.

RT = D kitten

RT = D+180 puppy

20T = D

25T = D + 180

Substitution

25T = 20T +180

5T = 180

T = 36s

It will take 4 seconds.

Step-by-step explanation:

It takes the puppy 25 seconds and the cat 20 seconds.

20+25=45

180 divided by 45 = 4

= 4 seconds.

36 seconds

Step-by-step explanation:

Distances covered in time t:

Puppy: 25t

Kitten: 20t

Assuming the kitten is 180m ahead of the puppy:

25t = 20t + 180

5t = 180

t = 36 seconds

4 sec

Step-by-step explanation:

Let

x> distance the kitten runs before being caught by the puppy

Remember that

The speed is equal to divide the distance by the time

v=d/t

solve for t

t=d/v

so

equate the time

x/20=(180-x)/25

25x=20(180-x)

25x=3,600-20x

25x+20x=3,600

x=3,600/45=80 m

t=d/v=80/20=4 sec

or

t=(180-80)/25=100/25=4 sec

It will take 4 seconds.

Step-by-step explanation:

It takes the puppy 25 seconds and the cat 20 seconds.

20+25=45

180 divided by 45 = 4

= 4 seconds.

4 seconds

Let they meet after time 't' seconds

Let distance covered by puppy in 't' seconds be 'x' meters

So distance covered by kitten in 't' seconds is (180 - x ) meters

Time = Distance / Speed

so,

t = x / 25 for puppy

t = (180-x) / 20 for kitten

On solving,

x = 100 meters

t = 4 seconds

Step-by-step explanation:

we are starting with formula S=D/T; S= speed; D=distance; T=time

T= D/25 for puppy

T=(180-D)/20 for kitten

we are having 2 equations!

180 - D=20*T and D=25*T => 180-25*T=20*T =>180= 45*T => T=180/45

T=4 SEC

T=D/25=>D=4*25=100 METERS

SO THEY WILL MEET AFTER 4 SECONDS IF THEY SIMULTANEOUSLY START RUNNING TOWARD EACH OTHER!

The puppy will catch the kitten in 36 seconds!!

Step-by-step explanation:

36 sec

Step-by-step explanation:

Let

x> distance the kitten runs before being caught by the puppy

Remember that

The speed is equal to divide the distance by the time

v=d/t

solve for t

t=d/v

so

equate the time

x/20=(180+x)/25

25x=20(180+x)

25x=3,600+20x

25x-20x=3,600

x=3,600/5=720 m

t=d/v=720/20=36 sec

or

t=(720+180)/25=900/25=36 sec