Apuppy and a kitten are 180 meters apart when they see each other. the puppy can run at a speed of 25 m/sec, while the kitten can run at a speed of 20 m/sec. a how soon will they meet if they simultaneously start running towards each other?
Apuppy and a kitten are 180 meters apart when they see each other. the puppy can run at a speed of 25 m/sec, while the kitten can run at a speed of 20 m/sec. a how soon will they meet if they simultaneously start running towards each other?
Make two equations representing the position of each animal, p and k, for the puppy and kitten respectively.
p=25t and k=180+20t
The puppy will catch the kitten when p=k so we can say:
25t=180+20t subtract 20t from both sides
5t=180 divide both sides by 5
t=36
So the puppy will catch the kitten after 36 seconds.
It seems it should be the other way... . How soon will the puppy catch up with the kitten.
The way you have it the kitten will never catch the pup. There is already 180m between them so, the distance will only increase because the puppy runs faster than the cat.
If the puppy runs after the cat, will eventually catch up with it and can be calculated. Not the other way around.
If the pup runs after the cat, the distance between them will decrease and the pup will catch the cat.
RT = D kitten
RT = D+180 puppy
20T = D
25T = D + 180
Substitution
25T = 20T +180
5T = 180
T = 36s
It will take 4 seconds.
Step-by-step explanation:
It takes the puppy 25 seconds and the cat 20 seconds.
20+25=45
180 divided by 45 = 4
= 4 seconds.
36 seconds
Step-by-step explanation:
Distances covered in time t:
Puppy: 25t
Kitten: 20t
Assuming the kitten is 180m ahead of the puppy:
25t = 20t + 180
5t = 180
t = 36 seconds
4 sec
Step-by-step explanation:
Let
x> distance the kitten runs before being caught by the puppy
Remember that
The speed is equal to divide the distance by the time
v=d/t
solve for t
t=d/v
so
equate the time
x/20=(180-x)/25
25x=20(180-x)
25x=3,600-20x
25x+20x=3,600
x=3,600/45=80 m
t=d/v=80/20=4 sec
or
t=(180-80)/25=100/25=4 sec
It will take 4 seconds.
Step-by-step explanation:
It takes the puppy 25 seconds and the cat 20 seconds.
20+25=45
180 divided by 45 = 4
= 4 seconds.
4 seconds
Let they meet after time 't' seconds
Let distance covered by puppy in 't' seconds be 'x' meters
So distance covered by kitten in 't' seconds is (180 - x ) meters
Time = Distance / Speed
so,
t = x / 25 for puppy
t = (180-x) / 20 for kitten
On solving,
x = 100 meters
t = 4 seconds
Step-by-step explanation:
we are starting with formula S=D/T; S= speed; D=distance; T=time
T= D/25 for puppy
T=(180-D)/20 for kitten
we are having 2 equations!
180 - D=20*T and D=25*T => 180-25*T=20*T =>180= 45*T => T=180/45
T=4 SEC
T=D/25=>D=4*25=100 METERS
SO THEY WILL MEET AFTER 4 SECONDS IF THEY SIMULTANEOUSLY START RUNNING TOWARD EACH OTHER!
The puppy will catch the kitten in 36 seconds!!
Step-by-step explanation:
36 sec
Step-by-step explanation:
Let
x> distance the kitten runs before being caught by the puppy
Remember that
The speed is equal to divide the distance by the time
v=d/t
solve for t
t=d/v
so
equate the time
x/20=(180+x)/25
25x=20(180+x)
25x=3,600+20x
25x-20x=3,600
x=3,600/5=720 m
t=d/v=720/20=36 sec
or
t=(720+180)/25=900/25=36 sec