Apuppy and a kitten are 180 meters apart when they see each other. the puppy can run at a speed of 25 m/sec, while the kitten

Apuppy and a kitten are 180 meters apart when they see each other. the puppy can run at a speed of 25 m/sec, while the kitten can run at a speed of 20 m/sec. a how soon will they meet if they simultaneously start running towards each other?

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  1. Make two equations representing the position of each animal, p and k, for the puppy and kitten respectively.

    p=25t and k=180+20t  

    The puppy will catch the kitten when p=k so we can say:

    25t=180+20t  subtract 20t from both sides

    5t=180  divide both sides by 5

    t=36

    So the puppy will catch the kitten after 36 seconds.

  2. It seems it should be the other way... . How soon will the puppy catch up with the kitten.
    The way you have it the kitten will never catch the pup. There is already 180m between them so, the distance will only increase because the puppy runs faster than the cat.
    If the puppy runs after the cat, will eventually catch up with it and can be calculated. Not the other way around.
    If the pup runs after the cat, the distance between them will decrease and the pup will catch the cat.

    RT = D kitten
    RT = D+180 puppy

    20T = D
    25T = D + 180
    Substitution

    25T = 20T +180
    5T = 180
    T = 36s

  3. It will take 4 seconds.

    Step-by-step explanation:

    It takes the puppy 25 seconds and the cat 20 seconds.

    20+25=45

    180 divided by 45 = 4

    = 4 seconds.

  4. 36 seconds

    Step-by-step explanation:

    Distances covered in time t:

    Puppy: 25t

    Kitten: 20t

    Assuming the kitten is 180m ahead of the puppy:

    25t = 20t + 180

    5t = 180

    t = 36 seconds

  5. 4 sec

    Step-by-step explanation:

    Let

    x> distance the kitten runs before being caught by the puppy

    Remember that

    The speed is equal to divide the distance by the time

    v=d/t

    solve for t

    t=d/v

    so

    equate the time

    x/20=(180-x)/25

    25x=20(180-x)

    25x=3,600-20x

    25x+20x=3,600

    x=3,600/45=80 m

    t=d/v=80/20=4 sec

    or

    t=(180-80)/25=100/25=4 sec

  6. It will take 4 seconds.

    Step-by-step explanation:

    It takes the puppy 25 seconds and the cat 20 seconds.

    20+25=45

    180 divided by 45 = 4

    = 4 seconds.

  7. 4 seconds

    Let they meet after time 't' seconds

    Let distance covered by puppy in 't' seconds be 'x' meters

    So distance covered by kitten in 't' seconds is (180 - x ) meters

    Time = Distance / Speed

    so,

    t = x / 25   for puppy

    t = (180-x) / 20     for kitten

    On solving,

    x = 100 meters

    t = 4 seconds

  8. Step-by-step explanation:

    we are starting with formula S=D/T; S= speed; D=distance; T=time

    T= D/25 for puppy

    T=(180-D)/20 for kitten

    we are having 2 equations!

    180 - D=20*T   and D=25*T   =>  180-25*T=20*T =>180= 45*T => T=180/45

    T=4 SEC

    T=D/25=>D=4*25=100 METERS

    SO THEY WILL MEET AFTER 4 SECONDS IF THEY SIMULTANEOUSLY START RUNNING TOWARD EACH OTHER!

  9. 36 sec

    Step-by-step explanation:

    Let

    x> distance the kitten runs before being caught by the puppy

    Remember that

    The speed is equal to divide the distance by the time

    v=d/t

    solve for t

    t=d/v

    so

    equate the time

    x/20=(180+x)/25

    25x=20(180+x)

    25x=3,600+20x

    25x-20x=3,600

    x=3,600/5=720 m

    t=d/v=720/20=36 sec

    or

    t=(720+180)/25=900/25=36 sec

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