Arectangle has a width of 2cm and a perimeter of 25cm. find the length and the area .

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Arectangle has a width of 2cm and a perimeter of 25cm. find the length and the area .

2w + 2l = 25

2 * 2 + 2l = 25

Simplfiy.

4 + 2l = 25

Subtract 4 from both sides.

2l = 21

Divide both sides by 2.

l = 10.5

Now that we have the value of l, we can find the area.

A = lw

A = 10.5 * 2

A = 21.

The length is 10.5cm.

The area of the rectangle is 21cm^2

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step-by-step explanation:

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