Assume that lines that appear to be tangents are tangents. O is the center of the circle.

What is the value of x?

[tex]Assume that lines that appear to be tangents are tangents. O is the center of the circle. What is th[/tex]

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Assume that lines that appear to be tangents are tangents. O is the center of the circle.

What is the value of x?

[tex]Assume that lines that appear to be tangents are tangents. O is the center of the circle. What is th[/tex]

For the inscribed angles quiz the answers are:

1: d(44)

2: a(74)

3: a(13,464 miles)

4: d(3.5 ft)

5: b(9.2)

6: d(56 degrees)

7: c(69.5 degrees)

8: d(84)

I just just took the quiz. So like it’s right.

47

Step-by-step explanation:

The value of x is 45°

Option C is correct.

Step-by-step explanation:

Given the figure in which two tangents are drawn and

The measure of ∠O is 135°

we have to find the value of x.

By theorem radius from the center of circle is perpendicular to the tangent line i.e

∠OAB=∠OCB=90°

As OABC is a quadrilateral therefore sum of all angles equals to 360°

∠ABC+∠AOC+∠OAB+∠OCB=360°

x°+135°+90°+90°=360°

x+315°=360°

x=360°-315°=45°

Hence, the value of x is 45°

Option C is correct.

[tex]Assume that lines that appear to be tangent are tangent. o is the center of the circle. find the val[/tex]

x = 64.

Step-by-step explanation:

If PQ is a segment on a tangent to the circle at point Q (as per the question), then <OQP is a right angle, so m<OQP=90 degrees. The angles in the triangle OPQ will need to sum up to 180 degrees. We are given m<OPQ=26 degrees. It remains to be determined the angle x = 180 - 90 - 26 = 64.

X = 64

Step-by-step explanation:

Well you know the angle of P and that is 26

Consider angle Q and 90 angle add Angle Q+P

you get 116

Each triangle adds up to 180 degrees

take 116 and subtract that from 180

180 - 116 = 64

The value of x is 45°

Option C is correct.

Step-by-step explanation:

Given the figure in which two tangents are drawn and

The measure of ∠O is 135°

we have to find the value of x.

By theorem radius from the center of circle is perpendicular to the tangent line i.e

∠OAB=∠OCB=90°

As OABC is a quadrilateral therefore sum of all angles equals to 360°

∠ABC+∠AOC+∠OAB+∠OCB=360°

x°+135°+90°+90°=360°

x+315°=360°

x=360°-315°=45°

Hence, the value of x is 45°

Option C is correct.

the value of x is 45

Step-by-step explanation: its a little bit bigger than the 40 on the right

64

Hope That Helps!

NEED ONE MORE BRAINIEST

Hello!

A triangle is 180 degrees, and you are given one of the angles, which is ∠P = 26 degrees.

Angle Q is a right angle, and this triangle is therefore a right triangle, so one angle has to be 90 degrees, and the other two angles are acute.

So we can create a simple equation:

m∠P + m∠Q + m∠x = 180 degrees

26 + 90 + m∠x = 180

116 + m∠x = 180

-116 - 116

m∠x = 64 degrees.

The measure of angle x is equal to 64 degrees, which is the fourth choice.

The value of x is 45°

Option C is correct.

Step-by-step explanation:

Given the figure in which two tangents are drawn and

The measure of ∠O is 135°

we have to find the value of x.

By theorem radius from the center of circle is perpendicular to the tangent line i.e

∠OAB=∠OCB=90°

As OABC is a quadrilateral therefore sum of all angles equals to 360°

∠ABC+∠AOC+∠OAB+∠OCB=360°

x°+135°+90°+90°=360°

x+315°=360°

x=360°-315°=45°

Hence, the value of x is 45°

Option C is correct.

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