Assume that lines that appear to be tangents are tangents. O is the center of the circle.
What is the value of x?
[tex]Assume that lines that appear to be tangents are tangents. O is the center of the circle. What is th[/tex]
Assume that lines that appear to be tangents are tangents. O is the center of the circle.
What is the value of x?
[tex]Assume that lines that appear to be tangents are tangents. O is the center of the circle. What is th[/tex]
For the inscribed angles quiz the answers are:
1: d(44)
2: a(74)
3: a(13,464 miles)
4: d(3.5 ft)
5: b(9.2)
6: d(56 degrees)
7: c(69.5 degrees)
8: d(84)
I just just took the quiz. So like it’s right.
47
Step-by-step explanation:
The value of x is 45°
Option C is correct.
Step-by-step explanation:
Given the figure in which two tangents are drawn and
The measure of ∠O is 135°
we have to find the value of x.
By theorem radius from the center of circle is perpendicular to the tangent line i.e
∠OAB=∠OCB=90°
As OABC is a quadrilateral therefore sum of all angles equals to 360°
∠ABC+∠AOC+∠OAB+∠OCB=360°
x°+135°+90°+90°=360°
x+315°=360°
x=360°-315°=45°
Hence, the value of x is 45°
Option C is correct.
[tex]Assume that lines that appear to be tangent are tangent. o is the center of the circle. find the val[/tex]
x = 64.
Step-by-step explanation:
If PQ is a segment on a tangent to the circle at point Q (as per the question), then <OQP is a right angle, so m<OQP=90 degrees. The angles in the triangle OPQ will need to sum up to 180 degrees. We are given m<OPQ=26 degrees. It remains to be determined the angle x = 180 - 90 - 26 = 64.
X = 64
Step-by-step explanation:
Well you know the angle of P and that is 26
Consider angle Q and 90 angle add Angle Q+P
you get 116
Each triangle adds up to 180 degrees
take 116 and subtract that from 180
180 - 116 = 64
The value of x is 45°
Option C is correct.
Step-by-step explanation:
Given the figure in which two tangents are drawn and
The measure of ∠O is 135°
we have to find the value of x.
By theorem radius from the center of circle is perpendicular to the tangent line i.e
∠OAB=∠OCB=90°
As OABC is a quadrilateral therefore sum of all angles equals to 360°
∠ABC+∠AOC+∠OAB+∠OCB=360°
x°+135°+90°+90°=360°
x+315°=360°
x=360°-315°=45°
Hence, the value of x is 45°
Option C is correct.
the value of x is 45
Step-by-step explanation: its a little bit bigger than the 40 on the right
64
Hope That Helps!
NEED ONE MORE BRAINIEST
Hello!
A triangle is 180 degrees, and you are given one of the angles, which is ∠P = 26 degrees.
Angle Q is a right angle, and this triangle is therefore a right triangle, so one angle has to be 90 degrees, and the other two angles are acute.
So we can create a simple equation:
m∠P + m∠Q + m∠x = 180 degrees
26 + 90 + m∠x = 180
116 + m∠x = 180
-116 - 116
m∠x = 64 degrees.
The measure of angle x is equal to 64 degrees, which is the fourth choice.
The value of x is 45°
Option C is correct.
Step-by-step explanation:
Given the figure in which two tangents are drawn and
The measure of ∠O is 135°
we have to find the value of x.
By theorem radius from the center of circle is perpendicular to the tangent line i.e
∠OAB=∠OCB=90°
As OABC is a quadrilateral therefore sum of all angles equals to 360°
∠ABC+∠AOC+∠OAB+∠OCB=360°
x°+135°+90°+90°=360°
x+315°=360°
x=360°-315°=45°
Hence, the value of x is 45°
Option C is correct.
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