# At -32.7 °C, a gas takes up 0.750 mL. What temperature, in °C, would be needed to reduce the volume to half that amount?pleaseee

At -32.7 °C, a gas takes up 0.750 mL. What temperature, in °C, would be needed to reduce the volume to half that amount? pleaseee answer correctly

## This Post Has 3 Comments

1. Expert says:

i think it is true since you can test the answer and can use observations to complete it.

2. supergirl101911 says:

-152.92°C

Explanation:

Initial volume = 0.750 mL

Initial temperature = -32.7 °C (-32.7 + 273.15 K = 240.45 k)

Final temperature = ?

Final volume = 0.750 mL / 2= 0.375 mL

Solution:

The given problem will be solve through the Charles Law.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂ / V₁

T₂ =  240.45 k  × 0.375 mL / 0.750 mL

T₂ = 90.17 mL.K / 0.750 mL

T₂ = 120.23  K

Temperature in celsius:

120.23  K - 273.15 = -152.92°C

3. Expert says:

What are the choices?