At -32.7 °C, a gas takes up 0.750 mL. What temperature, in °C, would be needed to reduce the volume to half that amount?pleaseee

At -32.7 °C, a gas takes up 0.750 mL. What temperature, in °C, would be needed to reduce the volume to half that amount? pleaseee answer correctly

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  1. -152.92°C

    Explanation:

    Initial volume = 0.750 mL

    Initial temperature = -32.7 °C (-32.7 + 273.15 K = 240.45 k)

    Final temperature = ?

    Final volume = 0.750 mL / 2= 0.375 mL

    Solution:

    The given problem will be solve through the Charles Law.

    Mathematical expression:

    V₁/T₁ = V₂/T₂

    V₁ = Initial volume

    T₁ = Initial temperature

    V₂ = Final volume  

    T₂ = Final temperature

    Now we will put the values in formula.

    V₁/T₁ = V₂/T₂

    T₂ = T₁V₂ / V₁

    T₂ =  240.45 k  × 0.375 mL / 0.750 mL

    T₂ = 90.17 mL.K / 0.750 mL

    T₂ = 120.23  K

    Temperature in celsius:

    120.23  K - 273.15 = -152.92°C

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