At what temperature in K would CO2 gas have to be if 1.5 mol occupies a 5L

container at 777 kPa?

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At what temperature in K would CO2 gas have to be if 1.5 mol occupies a 5L

container at 777 kPa?

PIVI/T1 = P2V2/T2

T2 = P2V2T1/P1V1

17.8*0.612*28/0.723*13.5 = 16.34

273K and 1.0 atm would be more ideal

there all right good

explanation:

answer: your mm

explanation:

initial temperature=[tex]-3.31^{\circ}C[/tex]

Explanation:

Assuming that the given follows the ideal gas nature;

[tex]P_1=0.723atm[/tex]

[tex]V_1=13.5L[/tex]

[tex]T_1=?[/tex]

[tex]P_2=0.612atm[/tex]

[tex]V_2=17.8L[/tex]

[tex]T_2=28 ^{\circ}C =273+28K=301K[/tex]

mole of gass will remain same at any emperature:

[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]

putting all the value we get:

[tex]T_2 =269.7K =-3.31 ^{\circ} C[/tex]

initial temperature=[tex]-3.31^{\circ}C[/tex]

(4) 600 K and 0.5 atm