Home Chemistry At what temperature in K would CO2 gas have to be if 1.5 mol occupies a 5Lcontainer at 777 kPa? At what temperature in K would CO2 gas have to be if 1.5 mol occupies a 5Lcontainer at 777 kPa?Chemistry Montgomerykarloxc24xOctober 23, 20216 CommentsAt what temperature in K would CO2 gas have to be if 1.5 mol occupies a 5L container at 777 kPa?
initial temperature=[tex]-3.31^{\circ}C[/tex]Explanation:Assuming that the given follows the ideal gas nature;[tex]P_1=0.723atm[/tex][tex]V_1=13.5L[/tex][tex]T_1=?[/tex][tex]P_2=0.612atm[/tex][tex]V_2=17.8L[/tex][tex]T_2=28 ^{\circ}C =273+28K=301K[/tex]mole of gass will remain same at any emperature:[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]putting all the value we get:[tex]T_2 =269.7K =-3.31 ^{\circ} C[/tex]initial temperature=[tex]-3.31^{\circ}C[/tex]Reply
PIVI/T1 = P2V2/T2
T2 = P2V2T1/P1V1
17.8*0.612*28/0.723*13.5 = 16.34
273K and 1.0 atm would be more ideal
there all right good
explanation:
answer: your mm
explanation:
initial temperature=[tex]-3.31^{\circ}C[/tex]
Explanation:
Assuming that the given follows the ideal gas nature;
[tex]P_1=0.723atm[/tex]
[tex]V_1=13.5L[/tex]
[tex]T_1=?[/tex]
[tex]P_2=0.612atm[/tex]
[tex]V_2=17.8L[/tex]
[tex]T_2=28 ^{\circ}C =273+28K=301K[/tex]
mole of gass will remain same at any emperature:
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
putting all the value we get:
[tex]T_2 =269.7K =-3.31 ^{\circ} C[/tex]
initial temperature=[tex]-3.31^{\circ}C[/tex]
(4) 600 K and 0.5 atm