# Atheme park charges a flat fee of $500 for group bookings of more than 25 tickets, plus$20 per ticket

Atheme park charges a flat fee of $500 for group bookings of more than 25 tickets, plus$20 per ticket for up to 100 tickets and $17 per ticket thereafter. if x represents the number of tickets sold under the group booking option, complete the limit equation that represents the average cost per ticket as the number of tickets purchased becomes very high. ### Related Posts ## Which of the following are parallel to the line 2x+ 4y=16 ## 7.(06.02)Nami plotted the graph below to show the relationship between the temperature of her city ## 3. Lolly and Molly are reading a book. Lolly is on page 30 and reads 4 pages a minute.Molly is on page 40 and reads two pages ## On a scale drawling with the scale of 1 in to 5ft to aflagpole is 4 inches tall how tall is the actual flagpole ## Renting a trailer for 4 days costs$84. Renting the trailer for 5 days costs $100. Which of the following ## 9. Find the area of a circle having a circumference of 382. Round to the nearest tenth. Use 3.14 for 1. a. 1133.5 units b. 1078.6 ## This Post Has 5 Comments 1. Schoolworkspace453 says: The required equation is: $\lim_{x \to \infty} \frac{2500+17(x-100)}{x}=17$ Step-by-step explanation: Consider the provided information. Let x represents tickets sold. A theme park charges a flat fee of$500 for group bookings of more than 25 tickets, plus $20 per ticket for up to 100 tickets and$17 per ticket thereafter.

The charges for booking 100 tickets will be:

$500 + 20\times 100 = \2500$

If you by more than 100 tickets theme park charges $17, Thus, charges for x tickets will be = $2500+ 17(x - 100)$ The limit equation represents the average cost per ticket as the number of tickets purchased becomes very high. The Cost of one ticket of the theme park = $\lim_{x \to \infty} \frac{2500+17(x-100)}{x}$ Now solve the above limit equation that will gives you the average cost per ticket as the number of tickets purchased becomes very high. $\lim_{x \to \infty} \frac{2500+17(x-100)}{x}= \lim_{x \to \infty}\frac{2500}{x}+17-\frac{1700}{x}$ $\lim_{x \to \infty}\frac{2500}{x}+17-\frac{1700}{x}=0+17-0$ Hence, the cost per ticket is$17 as the number of tickets purchased becomes very high.

2. noah2o2o says:

It's all about multiplication, 25 x 500 = 12,500 + 20 = 12,520 + 17,000, your answer is $29,520 3. nkh69 says: $\lim_{x \to \infty} \frac{2500+17(x-100)}{x}=17$ Step-by-step explanation: Let the theme park sold number of tickets = x Theme park charges$500 for group booking more than 25 tickets.

In addition to this theme park charges $20 per ticket for up to 100 tickets. So charges of 100 tickets = 500 + (100×20) =$2500

For more than 100 tickets theme park charges $17, so charges for x tickets will be = 500 + (100×20) + 17(x - 100) = 2500 + 17(x - 100) Cost of one ticket of the theme park = $\frac{2500+17(x-100)}{x}$ Now we have to write the limit equation when number of tickets purchased becomes very high. $\lim_{x \to \infty} \frac{2500+17(x-100)}{x}=17$ [By solving limit as below $\lim_{x \to \infty} \frac{2500+17(x-100)}{x}= \lim_{x \to \infty}\frac{2500}{x}+17-\frac{1700}{x}$ since $\lim_{x \to \infty}(\frac{1}{x})=0$ Therefore, $\lim_{x \to \infty}\frac{2500}{x}+17-\frac{1700}{x}=0+17-0$ = 17 ] 4. janai9852 says: it's all about multiplication,, your answer is$29,520

Step-by-step explanation:

25 x 500 = 12,500 + 20 = 12,520 + 17,000,

5. jholland03 says:

$\lim_{n \to \infty} a_n \frac{2500+17(x-100)}{x} =17$

Step-by-step explanation: I got this correct on Edmentum.

$Atheme park charges a flat fee of 500 for group bookings of more than 25 tickets, plus 20 per tick$