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1. Throat diameter [tex]d_2[/tex]=28.60 mm

   Explanation:

    Bore diameter [tex]d_1=63mm[/tex]  ⇒[tex]A_1=3.09\times 10^{-3} m^2[/tex]

   Manometric deflection x=235 mm

   Flow rate Q=240 Lt/min⇒ Q=.004[tex]\frac{m^3}{s}[/tex]

   Coefficient of discharge [tex]C_d[/tex]=0.8

   We know that discharge through venturi meter

    [tex]Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}[/tex]

   [tex]h=x(\dfrac{S_m}{S_w}-1)[/tex]

   [tex]S_m[/tex]=13.6 for Hg and [tex]S_w[/tex]=1 for water.

   [tex]h=0.235(\dfrac{13.6}{1}-1)[/tex]

   h=2.961 m

   Now by putting the all value in

   [tex]Q=C_d\dfrac{A_1A_2\sqrt{2gh}}{\sqrt{A_1^2-A_2^2}}[/tex]

   [tex]0.004=0.8\times \dfrac{3.09\times 10^{-3} A_2\sqrt{2\times 9.81\times 2.961}}{\sqrt{(3.09\times 10^{-3})^2-A_2^2}}[/tex]

   [tex]A_2=6.42\times 10^{-4} m^2[/tex]

    ⇒[tex]d_2[/tex]=28.60 mm

   So throat diameter [tex]d_2[/tex]=28.60 mm

        

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2. answer:

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3. answer:

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   explanation:

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