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Aweight is attached to a spring that hangs from the ceiling of a problem 1: room. when the weight is

Posted on October 23, 2021 By Nayelimoormann 8 Comments on Aweight is attached to a spring that hangs from the ceiling of a problem 1: room. when the weight is

Aweight is attached to a spring that hangs from the ceiling of a problem 1: room. when the weight is pulled down and released, the position of the weight can be modeled using a sine or cosine function. initially, the weight hangs 40 cm from the floor. it is pulled down 10 cm and released. it takes 0.2 seconds to reach its maximum height above the floor. find an equation, using either sine or cosine, that gives the height of the weight above the floor (in cm) in terms of time. (5 points) you might want to find: the amplitude yo cof (a) the period (b) (c) the horizontal shift (optional) the vertical shift tfok (d) sketch a graph

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Comments (8) on “Aweight is attached to a spring that hangs from the ceiling of a problem 1: room. when the weight is”

  1. claudiagallegos26 says:
    October 23, 2021 at 5:29 pm

    Option C.

    Step-by-step explanation:

    The equation that models the position of the weight and time will be a sine wave.

    y = A sin(bt)

    where A = amplitude of the wave

    b = time period for a complete oscillation

    Since b = [tex]\frac{2\pi }{t}[/tex]

    It has been given in the question, Time period t = 3 sec.

    b = [tex]\frac{2\pi }{3}[/tex]

    Amplitude A = 2 in.

    Now we plug in the values of amplitude and time period in the standard equation.

    y = [tex]2sin(\frac{2\pi }{3}\times t)[/tex]

    y = [tex]2sin(\frac{2\pi t}{3})[/tex]

    Option C. is the answer.

    Reply
  2. jaylanmahone223 says:
    October 23, 2021 at 8:17 pm

    The given information are:
    time it takes for a single cycle - 8 seconds
    distance between highest and lowest point - 20 cm

    The coordinates of the first point would be
    (0,0)
    The coordinates of the highest points is
    (2,10)
    The coordinates of the midline is
    (4,0)
    The coordinates of the lowest point is
    (6,-10)
    The coordinates at time = 8 seconds is
    (8,0)

    Reply
  3. mprjug6 says:
    October 23, 2021 at 10:50 pm

    [tex]T=2\pi \sqrt{\frac{m}{k} }[/tex]

    Where T is the period, m is the mass of the object, and k is the spring constant. It is important to note that the amplitude of the oscillation has no effect on the period. 
    Which means the question should in fact say factors - the displacement will have no effect, nor will observing it in any way - the only two things there that will affect the period of the spring is changing the weight and the spring constant.

    Reply
  4. babyshazi says:
    October 23, 2021 at 11:16 pm

    When t=0 the circumference is 7

    Reply
  5. miguelsanchez1456 says:
    October 24, 2021 at 1:07 am

    This graph is nonlinear

    The initial displacement of the weight is 40cm

    The weight first returns to equilibrium when t=1/2

    Step-by-step explanation:

    thats the answer i only had time to give not to explain

    Reply
  6. jasminespets says:
    October 24, 2021 at 1:14 am

    I think the most accurate answer can be the last one d. 150-137=13lb; A change in weight is positive, because the weight increases. I also think that the weight decreases each time we lose, but there's no such an answer. I think that the last word of answer d is just incorrect. The weight decreases*

    Reply
  7. yaniravivas79 says:
    October 24, 2021 at 3:00 am

    [tex]y=2.5 \sin(\pi t)[/tex]

    Step-by-step explanation:

    Time period $T$ is 2 sec.

    $T=\frac{2\pi}{\omega}$

    $\therefore 2=\frac{2\pi}{\omega}$

    $\therefore \omega=\pi$

    The amplitude is half the distance between highest and lowest points.

    Thus, amplitude $A= 2.5$

    The equation to the SHM is:

    $y=A \sin (\omega t)$

    Or,

    $\boxed{y=2.5 \sin (\pi t)}$

    Reply
  8. yay47 says:
    October 24, 2021 at 5:44 am

    varying the displacement of the mass from its equilibrium position

    increasing the amount of time the oscillating system is observed

    keeping track of the precise position of the mass through time

    Explanation:

    The period of a mass-spring system is given by:

    [tex]T=2 \pi \sqrt{\frac{m}{k}}[/tex]

    where

    m is the mass hanging from the spring

    k is the spring constant

    As we can see from the formula, the period depends only on these two factors: mass and spring constant, and nothing else. Therefore, the following factors do not affect the period of the system:

    varying the displacement of the mass from its equilibrium position

    increasing the amount of time the oscillating system is observed

    keeping track of the precise position of the mass through time

    Reply

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