Azul spun a tri-color spinner twice. What is the probability that the spinner landed on the colors blue and green in any order? BB, BG, BY, GB, GG, GY, YB, YG, YY 2 ON 3 Acvate Win Gettings to

Skip to content# Azul spun a tri-color spinner twice. What is the probability that the spinner landed on the colors blue and green in any order? BB,

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Azul spun a tri-color spinner twice. What is the probability that the spinner landed on the colors blue and green in any order? BB, BG, BY, GB, GG, GY, YB, YG, YY 2 ON 3 Acvate Win Gettings to

The spinner is tri-colored, which means there are 3 sections on the spinner. One section is colored blue, one is colored green. Let the third section be colored x.

The outcomes on spinning the spinner twice will be:

(Blue, Blue), (Blue,Green), (Blue,x), (Green, Green), (Green, Blue), (Green, x), (x,x), (x,Blue), (x, Green)

Total number of outcomes = 9

We want to find the probability that spinner lands on the colors blue and green in any order. The favorable outcomes thus will be:

(Blue, Green) and (Green, Blue)

Number of favorable outcomes = 2

The probability that the spinner landed on the colors blue and green in any order = 2/9

So, this means there are a 2 in 9 chances that the spinner landed on the colors blue and green in any order?

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

2/9

Step-by-step explanation:

no, because the sides are not congruent

[tex]Is the following shape a square? how do you know? [/tex]

The Probability that the spinner landed on the colors blue and green in any order = 2/9

Step-by-step explanation:

Given - Azul spun a tri-color spinner twice.

To find - What is the probability that the spinner landed on the colors blue and green in any order?

Solution -

Given that,

A tri-color spinner spun twice

So,

The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}

⇒n(S) = 9

Now,

Let A be an event that the spinner landed on the colors blue and green

So,

A = {BG, GB}

⇒n(A) = 2

Now,

Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)

= 2 ÷ 9

∴ we get

The Probability that the spinner landed on the colors blue and green in any order = 2/9