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1. The spinner is tri-colored, which means there are 3 sections on the spinner. One section is colored blue, one is colored green. Let the third section be colored x.

   The outcomes on spinning the spinner twice will be:
   (Blue, Blue), (Blue,Green), (Blue,x), (Green, Green), (Green, Blue), (Green, x), (x,x), (x,Blue), (x, Green)

   Total number of outcomes = 9

   We want to find the probability that spinner lands on the colors blue and green in any order. The favorable outcomes thus will be:
   (Blue, Green) and (Green, Blue)

   Number of favorable outcomes = 2

   The probability that the spinner landed on the colors blue and green in any order = 2/9 

   So, this means there are a 2 in 9 chances that the spinner landed on the colors blue and green in any order?

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2. point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

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3. 2/9

   Step-by-step explanation:

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4. no, because the sides are not congruent

   [tex]Is the following shape a square? how do you know? ​[/tex]

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5. The Probability that the spinner landed on the colors blue and green in any order = 2/9

   Step-by-step explanation:

   Given - Azul spun a tri-color spinner twice.

   To find - What is the probability that the spinner landed on the colors blue and green in any order?

   Solution -

   Given that,

   A tri-color spinner spun twice

   So,

   The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}

   ⇒n(S) = 9

   Now,

   Let A be an event that the spinner landed on the colors blue and green

   So,

   A = {BG, GB}

   ⇒n(A) = 2

   Now,

   Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)

            = 2 ÷ 9

   ∴ we get

   The Probability that the spinner landed on the colors blue and green in any order = 2/9

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