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Br2 + Sn -> 2Br^- + Sn^2+species oxidized:species reduced:oxidizing agent:reducing agent:As the reaction proceeds,

Posted on October 23, 2021 By Mem8163 4 Comments on Br2 + Sn -> 2Br^- + Sn^2+species oxidized:species reduced:oxidizing agent:reducing agent:As the reaction proceeds,

Br2 + Sn -> 2Br^- + Sn^2+ species oxidized:
species reduced:
oxidizing agent:
reducing agent:

As the reaction proceeds, electrons are transferred from ___ to ___


[tex]Br2 + Sn -> 2Br^- + Sn^2+ species oxidized: species reduced: oxidizing agent: reducing agent:[/tex]

Chemistry

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Comments (4) on “Br2 + Sn -> 2Br^- + Sn^2+species oxidized:species reduced:oxidizing agent:reducing agent:As the reaction proceeds,”

  1. Expert says:
    October 23, 2021 at 4:42 pm

    Ejjekekekekekekkk kekrkrkekrk

    Reply
  2. Expert says:
    October 23, 2021 at 4:58 pm

    Hcn is the correct answer leave a good rate and .

    Reply
  3. Expert says:
    October 24, 2021 at 2:16 am

    the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. [tex]hbr[/tex] completely dissociates to [tex]h^+[/tex] and [tex]br-[/tex] ions. a is incorrect because [tex]h_2s[/tex] does not fully ionize to [tex]h^+[/tex] and [tex]hs^-[/tex] ions and some remain as the compound [tex]h_2s[/tex]. c and d are incorrect because, [tex]li_2o[/tex] and [tex]libr[/tex] do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both [tex]li_2o[/tex] and [tex]libr[/tex] have a complete octet so can not accept any electrons which disqualifies them as acids.

    Reply
  4. Expert says:
    October 24, 2021 at 5:41 am

    Noble gases is far right

    Reply

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