# Br2 + Sn -> 2Br^- + Sn^2+species oxidized:species reduced:oxidizing agent:reducing agent:As the reaction proceeds,

Br2 + Sn -> 2Br^- + Sn^2+ species oxidized:
species reduced:
oxidizing agent:
reducing agent:

As the reaction proceeds, electrons are transferred from ___ to ___

$Br2 + Sn -> 2Br^- + Sn^2+ species oxidized: species reduced: oxidizing agent: reducing agent:$

## This Post Has 4 Comments

1. Expert says:

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2. Expert says:

Hcn is the correct answer leave a good rate and .

3. Expert says:

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. $hbr$ completely dissociates to $h^+$ and $br-$ ions. a is incorrect because $h_2s$ does not fully ionize to $h^+$ and $hs^-$ ions and some remain as the compound $h_2s$. c and d are incorrect because, $li_2o$ and $libr$ do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both $li_2o$ and $libr$ have a complete octet so can not accept any electrons which disqualifies them as acids.

4. Expert says:

Noble gases is far right