Can someone please show me how to solve this it’ll make my day

[tex]Can someone please show me how to solve this it’ll make my day[/tex]

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Can someone please show me how to solve this it’ll make my day

[tex]Can someone please show me how to solve this it’ll make my day[/tex]

use m.a.t.h.w.a.y it very helpful with math

ADE 1/3

ABC 3/3

4.38 Grams of C

Explanation:

How many grams of C are required to react with 52.6grams of Fe2O2?

Fe2O2 + C = 2Fe + CO2

Ratio 1:1

Fe2O2 = 144 Molar Mass

Fe2O2 52.6/144 = 0.365Moles of Fe2O2

Fe =56grams/mole = Charge 2+, 3+

O = 16grams/mole = Charge 2-

C = 12grams/mole = Charge 4+

So Ratio is 1:1 so we only need 0.365Moles of C so 4.38grams