Consider mendel's pea plants in which a single gene determines whether the peas are yellow from the dominant allele y or green from the recessive allele y (when both alleles are y). according to the hardy-weinberg principle of equilibrium, what is the frequency of heterozygous individuals in a population under low selective pressure?
If a single gene Y determinates the colour of the peas than:
YY is dominant homozygous genotype-yellow phenotype
Yy is heterozygous genotype-yellow phenotype
Yy is recessive homozygous genotype-green phenotype.
Hardy-Weinberg equation: p2 + 2pq + q2 = 1, where
p2 is the frequency of dominant homozygous genotype,
2pq is the frequency of heterozygous genotype and
q2 is frequency of recessive homozygous genotype.
c. 2pq
Explanation:
an individual pea plant could be pp (YY), and thus produce yellow peas; pq (Yy), also yellow; or qq (yy), and thus producing green peas.the frequency of pq individuals is 2pq