# Consider the line 7x+8y=-5.What is the slope of a line perpendicular to this line?What is the slope of a line parallel to this line?

Consider the line 7x+8y=-5. What is the slope of a line perpendicular to this line?
What is the slope of a line parallel to this line?

## This Post Has 6 Comments

1. Expert says:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

2. alyssamaize says:

1) m=-2

2) C) y=-3/4x -6

3) D) y=2/5x-2

I don't understand 4 nor 5. My apologies.

6) Parallel

$Asap 15 points 1) determine the slope of the line that is perpendicular to the equation below. y = -$

3. kaliahgrey says:

Step-by-step explanation:

7x + 8y = -5

8y = -7x - 5

Divide the whole equation by 8

$\frac{8y}{8}=\frac{-7x}{8}-\frac{5}{8}\\\\y =\frac{-7}{8}x-\frac{5}{8}$

Parallel lines have same slope

Slope of the parallel line = (-7/8)

Slope of the line perpendicular to this line = -1/m  = -1 ÷ (-7/8)

$= (-1)*\frac{8}{-7}\\\\= \frac{8}{7}$

4. lilblakey69 says:

1) m=-2

2) C) y=-3/4x -6

3) D) y=2/5x-2

I don't understand 4 nor 5. My apologies.

6) Parallel

5. Expert says:

He secknd step was the answer to them

6. pattykline says:

It would be 1/3 then A,D,C,5/3,A respectively