Consider the line 7x+8y=-5.What is the slope of a line perpendicular to this line?What is the slope of a line parallel to this line?

Consider the line 7x+8y=-5. What is the slope of a line perpendicular to this line?
What is the slope of a line parallel to this line?

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  1. ∠1≅∠2 by the alternate exterior angles theorem.

    step-by-step explanation:

    given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

    we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

    we have to fill the missing statement.

    transitivity property states that if a = b and b = c, then a = c.

    now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

    hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

    the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

    ∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

    hence, the missing statement is ∠1≅∠2.

    so, ∠1≅∠2 by the alternate exterior angles theorem.

  2. 1) m=-2

    2) C) y=-3/4x -6

    3) D) y=2/5x-2

    I don't understand 4 nor 5. My apologies.

    6) Parallel

    [tex]Asap 15 points 1) determine the slope of the line that is perpendicular to the equation below. y = -[/tex]

  3. Step-by-step explanation:

    7x + 8y = -5

           8y = -7x - 5

    Divide the whole equation by 8

    [tex]\frac{8y}{8}=\frac{-7x}{8}-\frac{5}{8}\\\\y =\frac{-7}{8}x-\frac{5}{8}[/tex]

    Parallel lines have same slope

    Slope of the parallel line = (-7/8)

    Slope of the line perpendicular to this line = -1/m  = -1 ÷ (-7/8)

                                                                          [tex]= (-1)*\frac{8}{-7}\\\\= \frac{8}{7}[/tex]

     

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