Consider the line 7x+8y=-5. What is the slope of a line perpendicular to this line?
What is the slope of a line parallel to this line?
Consider the line 7x+8y=-5. What is the slope of a line perpendicular to this line?
What is the slope of a line parallel to this line?
∠1≅∠2 by the alternate exterior angles theorem.
step-by-step explanation:
given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f
we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.
we have to fill the missing statement.
transitivity property states that if a = b and b = c, then a = c.
now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .
hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.
the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4
∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.
hence, the missing statement is ∠1≅∠2.
so, ∠1≅∠2 by the alternate exterior angles theorem.
1) m=-2
2) C) y=-3/4x -6
3) D) y=2/5x-2
I don't understand 4 nor 5. My apologies.
6) Parallel
[tex]Asap 15 points 1) determine the slope of the line that is perpendicular to the equation below. y = -[/tex]
Step-by-step explanation:
7x + 8y = -5
8y = -7x - 5
Divide the whole equation by 8
[tex]\frac{8y}{8}=\frac{-7x}{8}-\frac{5}{8}\\\\y =\frac{-7}{8}x-\frac{5}{8}[/tex]
Parallel lines have same slope
Slope of the parallel line = (-7/8)
Slope of the line perpendicular to this line = -1/m = -1 ÷ (-7/8)
[tex]= (-1)*\frac{8}{-7}\\\\= \frac{8}{7}[/tex]
1) m=-2
2) C) y=-3/4x -6
3) D) y=2/5x-2
I don't understand 4 nor 5. My apologies.
6) Parallel
He secknd step was the answer to them
It would be 1/3 then A,D,C,5/3,A respectively