Consider the polynomial equation x(x-3)(x+6)(x-7)=0. what are the zeros of the equation?

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Consider the polynomial equation x(x-3)(x+6)(x-7)=0. what are the zeros of the equation?

The zeros are 0, 3, -6 and 7.

B, D, E, and F

x = -6, 0 , 3, 7

Step-by-step explanation:

The zeros of a polynomial are the solutions to its factored set equal to 0. Using the zero -product property, you can set each factor of the polynomial equal to 0. Each one will solve to specific solution for it.

The polynomial has factors x, x-3, x+6 and x-7. Set each equal to 0 and solve.

x = 0

x - 3 = 0 has solution x = 3

x + 6 = 0 has solution x = -6

x - 7 = 0 has solution x = 7

The zeros of the polynomial are x = -6, 0 , 3, 7.

Anything times zero is equal to zero

hence for,

x(x-3)(x+6)(x-7)=0

only one of the groups/parenthesis must be equal to zero

therefore

x=0

x-3=0

x+6=0

x-7=0

just solve for all the x's, all those values are considered zeros of the equation

I believe the answers are -6,0 and 3 because if you plug each one into the equation you get the product of 0

If looking for the answer it would be 0, 3, -6, 7

0, 3, -6, 7

This is because if you plug in these numbers, atleast one of the binomials would equal zero

Since this equation is equal to zero, one of the factors has to equal zero. For example 0 x anything will equal zero. So set each individual factor to zero

X=0

(X-3)=0

(X+6)=0

(X-7)=0

So the first one is just zero X=0

Add 3 to the other side X=3

Subtract 6 X=-6

Add 7 X=7

So your zeros would be X=0,3,-6,7

x=0,3,-6,7

Step-by-step explanation:

set each factor equal to zero and then solve for x.

It should be 0,3, -6, and 7

Hello :

x(x-3)(x+6)(x-7)=0

x=0 or x-3=0 or x+6=0 or x-7=0

x=0 or x=3 or x=-6 or x=7

the zeros of the equation : 0 , 3 , -6 , 7