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1. The answer should be D

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2. The equation for the Kinetic Energy, [tex]KE_e[/tex], of the photo-emitted electrons is given as follows;

   [tex]KE_e = h\cdot f- BE[/tex]

   Please find attached the required plot of the kinetic energy versus the frequency

   Explanation:

   The equation for the Kinetic Energy, [tex]KE_e[/tex], of the photo-emitted electrons is given as follows;

   [tex]KE_e = h\cdot f- BE[/tex]

   Where:

   h = Planck's constant = 6.63×10⁻³⁴ J·s

   f = Frequency

   BE = Binding Energy = 2.71 eV  for Calcium metal

   f₀ = Threshold frequency for the material

   The ionization energy is the energy required to free an electron from an isolated atom

   [tex]Ultraviolet photoelectron spectroscopy (UPS) is an important analytical tool used to characterize th[/tex]

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