Do the tests performed to identify DNA exclude the presence of RNA? Posted on October 23, 2021 By Bgallman153p71edg 4 Comments on Do the tests performed to identify DNA exclude the presence of RNA? Do the tests performed to identify DNA exclude the presence of RNA? Chemistry
so the answer is noboth DNA and RNA are together.Explanation:DNA and RNA can also be ISOLATED from the same. biological sampleReply
DNA and RNA can also be ISOLATED from the same biological sample.So the answer is no, both DNA and RNA are together.Reply
answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/molexplanation :let us write down the given equationsequation 1 : [tex]4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol[/tex]equation 2 : [tex]2x (s) + 3cl_{2} (g) \rightarrow 2xcl_{3} (s) h rxn = -800 kj/mol[/tex]equation 3 : [tex]4xcl_{3} (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) + 6cl_(2} h rxn = -200 kj/mol[/tex]let us use hess's law to find out which 2 equations can be added to get the third equation.let us reverse equation 2 and multiply it by 2. the new equation that we get is,equation 4 : [tex]4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+800) \times 2 kj/mol[/tex]let us add equation 1 & 4[tex]4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol[/tex][tex]4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+1600) kj/mol[/tex][tex]4xcl_{3} )s) + 3o_{2} \rightarrow 2x_{2}o_{3} (s) + 6cl_{2} (g) h rxn = (+1000) kj/mol[/tex]the above equation is similar to equation 3 but has different value for dhrxn.therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/molReply
so the answer is no
both DNA and RNA are together.
Explanation:
DNA and RNA can also be ISOLATED from the same. biological sample
The answer is 4 i don't know if its right let me see.
DNA and RNA can also be ISOLATED from the same biological sample.
So the answer is no, both DNA and RNA are together.
answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol
explanation :
let us write down the given equations
equation 1 : [tex]4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol[/tex]
equation 2 : [tex]2x (s) + 3cl_{2} (g) \rightarrow 2xcl_{3} (s) h rxn = -800 kj/mol[/tex]
equation 3 : [tex]4xcl_{3} (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) + 6cl_(2} h rxn = -200 kj/mol[/tex]
let us use hess's law to find out which 2 equations can be added to get the third equation.
let us reverse equation 2 and multiply it by 2. the new equation that we get is,
equation 4 : [tex]4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+800) \times 2 kj/mol[/tex]
let us add equation 1 & 4
[tex]4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol[/tex]
[tex]4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+1600) kj/mol[/tex]
[tex]4xcl_{3} )s) + 3o_{2} \rightarrow 2x_{2}o_{3} (s) + 6cl_{2} (g) h rxn = (+1000) kj/mol[/tex]
the above equation is similar to equation 3 but has different value for dhrxn.
therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol