Enzo and beatriz are playing games at their local arcade.

incredibly, enzo wins 5 tickets from every game, and beatriz wins 11 tickets from every game. when they stopped playing games, enzo and beatriz had won the same number of total tickets.

what is the minimum number of games that enzo could have played?

The minimum number of games he could play is 11.

11 times

Step-by-step explanation:

In order for Enzo to have the same amount of tickets as Beatriz, the following equation must be met:

Number of tickets to be equal is 5*11 = 55

So, they both have 55 tickets, and that means Enzo played 11 times.

Given :Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game.We need to find the minimum number of games that Enzo could have played to win the same number of tickets.

The minimum number of games that Enzo could have played to win the same number of tickets Will be the least common multiple of 11 and 5.

The factors of 11 and 5 are

11=11x1

5= 5x1

Least common multiply = 11x5=5.

The minimum number of games that Enzo could have played to win the same number of tickets is 55.

Enzo played 11 games and Beatriz played 5 games, they both made a total of 55 tix each.

Dont let it confuse you too much.

Logic says that the first time 11 and 5 is in the same multiplication table is at 55.

This can also be found doing: 5*11=55

55/5=11 (this step is far from necisarry)

He needs to play 11 games, if beatriz won 5.

Find the least common multipule

factor each

huh, they're both prime

answer is to just multiply them

11*5=55

minimum nmber of tickets they could have earned was 55

Ooh! I know this question. I just did it. But anyways, the answer is Enzo played 11 games.

Step-by-step explanation:

its 11

Step-by-step explanation:

Beatriz 11 x 5 =55

so Enzo 5x11=55

think about it as the left is the number of tickets per game and on the right how many games they played see ez.