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Enzo and beatriz are playing games at their local arcade. incredibly, enzo wins 5 tickets from every

Posted on October 23, 2021 By Salvadorperez26 8 Comments on Enzo and beatriz are playing games at their local arcade. incredibly, enzo wins 5 tickets from every

Enzo and beatriz are playing games at their local arcade.
incredibly, enzo wins 5 tickets from every game, and beatriz wins 11 tickets from every game. when they stopped playing games, enzo and beatriz had won the same number of total tickets.
what is the minimum number of games that enzo could have played?

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Comments (8) on “Enzo and beatriz are playing games at their local arcade. incredibly, enzo wins 5 tickets from every”

  1. babyari18 says:
    October 23, 2021 at 1:09 pm

    The minimum number of games he could play is 11.

    Reply
  2. MansellS5529 says:
    October 23, 2021 at 2:18 pm

    11 times

    Step-by-step explanation:

    In order for Enzo to have the same amount of tickets as Beatriz, the following equation must be met:

    Number of  tickets to be equal is 5*11 = 55

    So, they both have 55 tickets, and that means Enzo played 11 times.

    Reply
  3. trapdee61p3sj8r says:
    October 23, 2021 at 3:29 pm

    Given :Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game.We need to find the minimum number of games that Enzo could have played to win the same number of tickets.

    The  minimum number of games that Enzo could have played to win the same number of tickets Will be the least common multiple of 11 and 5.

    The  factors of 11 and 5 are

    11=11x1

    5= 5x1

    Least common multiply = 11x5=5.

     The minimum number of games that Enzo could have played to win the same number of tickets is 55.

    Reply
  4. xxaurorabluexx says:
    October 23, 2021 at 4:07 pm

    Enzo played 11 games and Beatriz played 5 games, they both made a total of 55 tix each.

    Reply
  5. nerissa5 says:
    October 23, 2021 at 4:17 pm

    Dont let it confuse you too much.
    Logic says that the first time 11 and 5 is in the same multiplication table is at 55.
    This can also be found doing: 5*11=55
    55/5=11 (this step is far from necisarry)

    He needs to play 11 games, if beatriz won 5.

    Reply
  6. bougiehairstudios says:
    October 23, 2021 at 11:31 pm

    Find the least common multipule

    factor each

    huh, they're both prime

    answer is to just multiply them
    11*5=55
    minimum nmber of tickets they could have earned was 55

    Reply
  7. nuckols says:
    October 24, 2021 at 5:48 am

    Ooh! I know this question. I just did it. But anyways, the answer is Enzo played 11 games.

    Step-by-step explanation:

    Reply
  8. edconsys says:
    October 24, 2021 at 6:09 am

    its 11

    Step-by-step explanation:

    Beatriz 11 x 5 =55

    so Enzo 5x11=55

    think about it as the left is the number of tickets per game and on the right how many games they played see ez.

    Reply

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